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aalyn [17]
3 years ago
12

Write formulas for the binary ionic compounds formed between the following elements: a. Potassium and iodine b. Magnesium and ch

lorine c. Sodium and sulfur d. Aluminum and sulfur e. Aluminum and nitrogen
Chemistry
1 answer:
lianna [129]3 years ago
5 0

i think it's B Magnesium and chlorine



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A sealed container holding 0.0255 L of an ideal gas at 0.979 atm and 67 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w
Aliun [14]

Answer:

0.904 atm

Explanation:

Using Gay Lusaac's law where there is no change in Volume. The pressure changes directly proportional to absolute T°

P₁/T₁ = P₂/T₂

P₁T₂/T₁

P₂ = \frac{0.979 atm * 314k }{340k}

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3 years ago
A potassium hydroxide (KOH) solution has a molar concentration of 0.065 M, calculate the [H3O+], [OH-] and pH of the solution.
Tanya [424]

Answer:

1) [OH⁻] = 0.065 M

2) [H₃O⁺] = 1.54 x 10⁻¹³ M.

3)  pH = 12.81.

Explanation:

HCl is completely dissociated yo its ions in solution:

<em>KOH + H₂O  → H₃O⁺ + K⁺ + OH⁻, </em>

<em></em>

1) [OH⁻] = 0.065 M.

<em>2) [H₃O⁺]: </em>

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(0.065 M) = 1.54 x 10⁻¹³ M.

<em>3) pH: </em>

For strong acids like HCl:

pH = - log[H₃O⁺] = - log[1.54 x 10⁻¹³ M] = 12.81.

4 0
3 years ago
What would happen to the kinetic energy of an object if you doubled the mass
Maurinko [17]
Because kinetic energy is proportional to the velocity squared, increases in velocity will have an exponentially greater effect on translational kinetic energy. Doubling the mass of an object will only double its kinetic energy, but doubling the velocity of the object will quadruple its velocity.

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7 0
3 years ago
Read 2 more answers
What volume does 2800mg of nitrogen gas occupy at 98Kpa and -10 C?
Evgen [1.6K]

Answer:

2.23L

Explanation:

Using the general gas law as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

Mass of nitrogen = 2800mg

Since 1g = 1000mg

2800mg = 2800/1000

= 2.8g

Using mole = mass ÷ molar mass

Molar mass of nitrogen gas (N2) = 28g/mol

mole = 2.8/28

mole of N2 gas = 0.1mol

Pressure = 98kPa

1 kilopascal (kPa) = 1000pascal (pa)

98kPa = 98 × 1000

= 98000pascal

Since 1 Pascal = 9.869 × 10^-6 atmosphere (atm)

98000pascal = 98000 × 9.869 × 10^-6

= 0.967atm

Temperature = -10°C

Kelvin = °C + 273

Kelvin = -10 + 273

K = 263K

Hence, using PV = nRT

0.967 × V = 0.1 × 0.0821 × 263

0.967V = 2.159

V = 2.159/0.967

V = 2.23

Volume of Nitrogen gas = 2.23 L

6 0
3 years ago
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