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Pani-rosa [81]
2 years ago
8

Two ropes are attached to a 40-kg object. The first rope applies a force of 25 N and the second, 40 N. If the two ropes are perp

endicular to each other, what is the resultant acceleration of the object?
Physics
1 answer:
kifflom [539]2 years ago
8 0

Answer:

1.2 m/s^2

Explanation:

I will ignore gravity and friction....and will choose 25 N as UP and 40 N to Left (see diagram)

Resultant force:   R^2 = 25^2 + 40^2        R = sqrt(2225)=47 N

F = ma

F/m = a  

47 N / 40 kg = a = 1.2 m/s^2

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Power rating = volts x amps

Power rating = 7.5 x 120 = 900 watts

Answer: 900 watts

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2 years ago
A ________ is a rigid layer that surrounds a plant cell, providing structural support.
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Answer:

cell wall

Explanation:

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d. nothing

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a balloon inflated in a room at 297k has a volume of 4.00 l. the balloon is then heated to a temperature of 331 k. what is the n
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V2 = 4.4579 L

Since pressure is constant, use Charle’s law.
Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

V(olume) 1 = V(olume) 2
————— —————
T(emperature) 1 T(emperature)2

4.00 L = V2
———- ———
297 K 331 K

Cross multiply
(4.00 L x 331 K) = (297 K x V2)
Simplify
1324 L/K = 297 K x V2
Isolate V2 by dividing out 297 K
1324 L/K = V2
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V2 = 4.4579 L

Round to significant digits if required
7 0
2 years ago
The 68-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P
bogdanovich [222]

Explanation:

Mass of the crate, m = 68 kg

We need to find the resulting acceleration if :

(a) Force, P = 0

P = m a

⇒ a = 0

(b) P = 181 N

a=\dfrac{P}{m}

a=\dfrac{181\ N}{68\ kg}

a=2.67\ m/s^2

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a=\dfrac{P}{m}

a=\dfrac{352\ N}{68\ kg}

a=5.17\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
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