Answer:
The greenhouse effect is the process by which radiation from a planet's atmosphere warms the planet's surface to a temperature above what it would be without this atmosphere. Radiatively active gases in a planet's atmosphere radiate energy in all directions.
The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.
<h3>How do we calculate grams from moles?</h3>
Grams (W) of any substance will be calculated by using their moles (n) through the following equation:
M = molar mass
And moles of the gas will be calculated by using the ideal gas equation as:
P = pressure = 1atm
V = volume = 40L
n = moles = ?
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 200K
On putting these values on the above equation, we get
n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles
- Now grams of hydrogen gas will be calculated by using the first equation as:
W = (2.44mol)(2g/mol) = 4.88g
Hence required mass of hydrogen gas is 4.88g.
To know more about ideal gas equation, visit the below link:
brainly.com/question/15046679
#SPJ1
Answer:
d) The dilution equation works because the number of moles remains the same.
Explanation:
Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and <em>M</em>₁<em>V</em>₁ = 1 mol.
Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.
The volume has doubled, but the volume has halved, and <em>M</em>₂<em>V</em>₂ = 1 mol.
b) <em>Wrong</em>. The molar concentration changes on dilution.
c) <em>Wrong</em>. The volume changes on dilution.
a) <em>Wrong</em>, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula <em>M</em>₁<em>V</em>₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.
Answer:
there will be more miles of reactants
Answer:

Explanation:
Given that:-
![rate = k[NH_4^+][NO_2^-]](https://tex.z-dn.net/?f=rate%20%3D%20k%5BNH_4%5E%2B%5D%5BNO_2%5E-%5D)
k = 
![[NH_4^+]=0.301\ M](https://tex.z-dn.net/?f=%5BNH_4%5E%2B%5D%3D0.301%5C%20M)
![[NO_2^-]=0.160\ M](https://tex.z-dn.net/?f=%5BNO_2%5E-%5D%3D0.160%5C%20M)
So,

<u>
is the rate of the reaction at that temperature if [NH4+] = 0.301 M and [NO2−] = 0.160 M.</u>