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-BARSIC- [3]
2 years ago
10

if the atmospheric pressure and temperature stay the same how would an increase in humidity affect takeoff performance

Physics
1 answer:
Mariulka [41]2 years ago
4 0

High-density altitude and high humidity do not ever go hand in hand. If high humidity does exist, however, it exists wise to add 10 percent to your calculated takeoff distance and expect a reduced climb rate.

With a longer takeoff distance, the air exists less dense.

<h3>How do atmospheric temp pressure and rel humidity affects aircraft performance?</h3>

Several elements (altitude/pressure, temperature, and humidity) affect air density. A more elevated altitude, low-pressure area, higher temperature, and increased humidity all contain one effect: they lower the density of the air. And as a consequence of that: a decrease in aircraft and engine performance.

Humidity reduces the implementation of most aircraft, not only because of its effect on the wings but also effect on the engines. Humidity contains a significant effect on the path of plane flies. This exists due to the weight of the air when it exists in humid.

To learn more about humidity refer to:

brainly.com/question/21494654

#SPJ4

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The type of rocks are magma and the igneous rocks.
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Which instrument is used to measure liquid volume?
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Volumetric cylinders and volumetric flasks

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Momentum for a system can be conserved in one direction while not being conserved in another. What is the anglebetween the direc
katrin [286]

Answer:

90°

Explanation:

The angle will be 90° when momentum for a system can be conserved in one direction while not being conserved in another.

The example can be

If we apply force on an object horizontally in west direction, then as in other direction south or north we cannot apply the principal of momentum conservation.

5 0
3 years ago
The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .
vlabodo [156]

Answer: 90\°

Explanation:

The Compton Shift \Delta \lambda in wavelength when the photons are scattered is given by the following equation:

\Delta \lambda=\lambda_{c}(1-cos\theta)     (1)

Where:

\lambda_{c}=2.43(10)^{-12} m is a constant whose value is given by \frac{h}{m_{e}c}, being h the Planck constant, m_{e} the mass of the electron and c the speed of light in vacuum.

\theta) the angle between incident phhoton and the scatered photon.

We are told the maximum Compton shift in wavelength occurs when a photon isscattered through 180\°:

\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))     (2)

\Delta \lambda_{max}=\lambda_{c}(1-(-1))    

\Delta \lambda_{max}=2\lambda_{c}     (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)      (4)

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)      (5)

If we want \frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}, 1-cos\theta   must be equal to 1:

1-cos\theta=1   (6)

Finding \theta:

1-1=cos\theta

0=cos\theta  

\theta=cos^{-1} (0)  

Finally:

\theta=90\°    This is the scattering angle that will produce \frac{1}{4}\Delta \lambda_{max}      

7 0
3 years ago
6. Sandy adds 3 sugar packets to her tea in order to make it sweeter. She stirs in the sugar and then takes a sip. She notices t
irina1246 [14]

Answer:

C.Supersaturated

Explanation:

There are three types of solution:

<u>SATURATED SOLUTION</u>:

It is the solution that contains maximum amount of solute dissolved in a solution in normal conditions.  

<u>UNSATURATED SOLUTION</u>:

It is the solution that contains less than the maximum amount of solute dissolved in a solution in normal conditions. It has space for more solute to be dissolved in it.

<u>SUPERSATURATED SOLUTION:</u>

It contains more than the maximum amount of solute dissolved in it. Such a solution has no capacity to dissolve any more solute under any conditions.

Since the sugar is no more dissolving in the tea and has settled down. Therefore, the solution is:

<u>C.Supersaturated</u>

7 0
3 years ago
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