Give the oxidation state of sulfur in (d) H₂S ;
1 answer:
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Answer:
Explanation:
The total mole of added = 15 × 1 × 10⁻³
= 15 × 10⁻³ mole
= 15 mmoles
the number of moles of NaOH added in order to neutralize the excess acid = 0.5905 × 29.393 = 17.36 mmoles
the equation for the reaction is:
2NaOH + -------->
i.e
2 moles of NaOH react with
1 moles of NaOH will react with 1/2
17.36 mmoles of NaOH = 1/2 × 17.36 mmoles of
= 8.68 mmoles
Number of moles of that react with MCO₃ = Total moles of
added - moles of
reacted with NaOH
= (15 - 8.68) mmoles
= 6.32 mmoles
+
------>
+
+
1 mole of react with 1 mole of
6.32 mmoles of = 6.32 mmoles of
number of moles of = 6.32 10⁻³ moles
mass of (carbonate salt) = 0.533 g
molar mass of = (M+60)g/mol
We all know that ;
number of moles = mass/molar mass
Then:
6.32 10⁻³ = 0.533 / (M+60)
(M+60) = 0.533/ 6.32 10⁻³
M + 60 = 84.34
M = 84.34 - 60
M = 24.34
Thus the element with the atomic mass of 24.34 is Chromium
The chemical formula for the compound is :
setup 1 : to the right
setup 2 : equilibrium
setup 3 : to the left
<h3>Further explanation</h3>The reaction quotient (Q) : determine a reaction has reached equilibrium
For reaction :
aA+bB⇔cC+dD
Comparing Q with K( the equilibrium constant) :
K is the product of ions in an equilibrium saturated state
Q is the product of the ion ions from the reacting substance
Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)
Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium
Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)
Keq = 6.16 x 10⁻³
Q for reaction N₂O₄(0) ⇒ 2NO₂(g)
Setup 1 :
Q<K⇒The reaction moved to the right (products)
Setup 2 :
Q=K⇒the system at equilibrium
Setup 3 :
Q>K⇒The reaction moved to the left (reactants)