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Irina18 [472]
4 years ago
12

Sound is caused by the _____ air particles (waves)

Physics
1 answer:
Sav [38]4 years ago
5 0

Answer:

Sound travels in air as a series of compressions and rarefactions. When an object vibrates it will move back and forth. As it moves forth, it pushes adjacent air particles. ... This is a compression: an area of high pressure that moves along the direction of the sound wave.

Explanation:

adjacent is the answer

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A uniform meter stick of mass $M$ has a half-filled can of fruit juice of mass $m$ attached to one end. The meter stick and the
notka56 [123]

Answer:

111.6 g

Explanation:

Given

m + M = 2.58 / 9.8

= 0.2632 kg

When the can of fruit juice is balance from scale , we get following relation

M x ( 50 - 21.2 ) = m x 21.2 ( balancing the torque due to weight of scale and can about the balancing point )

M x 28.8 = 21.2 m

= 21.2 ( 0.2632 - M )

= 5.58 - 21.2 M

M ( 28.8 + 21.2 ) = 5.58

M = .1116 kg

= 111.6 g

7 0
4 years ago
Which process repeatedly moves matter between different forms on Earth?
ASHA 777 [7]
The answer to your question is b) the natural law
6 0
3 years ago
Read 2 more answers
A 300 cm rope under a tension of 120 N is set into oscillation. The mass density of the rope is 120 g/cm. What is the frequency
Vikki [24]

Answer:

Explanation:

f = \sqrt{T/(m/L)} / 2L

T = 120 N

L = 3.00 m

(m/L) = 120 g/cm(100 cm/m / 1000 g/kg) = 12 kg/m

                                                  (wow that's massive for a "rope")

f = \sqrt{120/12} /(2(3)))

f = \sqrt{10\\}/6 = 0.527 Hz

This is a completely silly exercise unless this "rope" is in space somewhere as the weight of the rope (353 N on earth) far exceeds the tension applied.

A much more reasonable linear density would be 120 g/m resulting in a frequency of √1000/6 = 5.27 Hz on a rope that weighs only 3.5 N

5 0
3 years ago
Harry Potter or Pokemon Sword?
Dominik [7]

Answer Pokémon sword

#Pokémon sword

Explanation:
I would rather prefer a sword
4 0
3 years ago
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A 12-V car battery supported a current of 150 mA to bulb calculate the power absorbed by the bulb over an interval of 20 mintues
ASHA 777 [7]

Answer:

  • +1.8W
  • 2,160J

Explanation:

First, we need to solve for the power absorbed by the bulb.

Formula [ p = vi ]

p = 12 * 150 * 10^-3

p = +1.8W

Second, we can solve for the power aborbed in a interval of 20 minutes.

Formula [ e = vit ]

e = 12 * 150 * 10^-3 * 20 * 60

e = 2,160J

Just a note that "20 * 60" represents the time given in seconds.

Best of Luck!

7 0
2 years ago
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