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oksano4ka [1.4K]
2 years ago
5

According to Coulomb’s Law, what happens to the force when the distance increase between 2 particles?

Physics
1 answer:
ohaa [14]2 years ago
8 0

Answer:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, <u>the attraction or repulsion becomes weaker</u>, decreasing to one-fourth of the original value.

Explanation:

Coulomb’s law, mathematical description of the electric force between charged objects. Formulated by the 18th-century French physicist Charles-Augustin de Coulomb, it is analogous to Isaac Newton’s law of gravity.

Both gravitational and electric forces decrease with the square of the distance between the objects, and both forces act along a line between them. In Coulomb’s law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. Thus, charge determines how electromagnetism influences the motion of charged objects. Charge is a basic property of matter. Every constituent of matter has an electric charge with a value that can be positive, negative, or zero.

Coulomb's Law says that the force between 2 charges is proportional to the product of the quantities of charge on each and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is F=k\frac{q_{1}q_{2}   }{r^{2} }.

F is the force.

k is the Coulomb's constant (8.987*10^{9} \frac{Nm^{2} }{C^{2} }).

q_{1} is the electric charge of object 1.

q_{2} is the electric charge of object 2.

r is the distance between the two charges.

Electric force is inversely proportional to (r^{2}) instead of (r). As the distance between charges increases, the electric force decreases by a factor of \frac{1}{r^{2} }.

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A man strikes one end of a thin rod with a hammer. The speed of sound in the rod is 15 times the speed of sound in air. A woman,
lina2011 [118]

Answer:

44.1 m

Explanation:

<u>Given:</u>

  • V_a = speed of sound in air = 343 m/s
  • V_r = speed of sound in the rod = 15V_a
  • \Delta t = times interval between the hearing the sound twice = 0.12 s

<u>Assumptions:</u>

  • l = length of the rod
  • t = time taken by the sound to travel through the rod
  • T = time taken by the sound to travel to through air to the same point = t+\Delta t = t+0.12\ s

We know that the distance traveled by the sound in a particular medium is equal to the product of the speed of sound in that medium and the time taken.

For traveling sound through the rod, we have

l=V_r t\\\Rightarrow t = \dfrac{l}{V_r}..........eqn(1)

For traveling sound through the air to the women ear for traveling the same distance, we have

l=V_aT\\\Rightarrow l=V_a(t+0.12)\\\Rightarrow l=V_a(\dfrac{l}{V_r}+0.12)\,\,\,\,\,\,(\textrm{From eqn (1)})\\\Rightarrow l=V_a(\dfrac{l}{15V_a}+0.12)\\\Rightarrow l=\dfrac{l}{15}+0.12V_a\\\Rightarrow l-\dfrac{l}{15}=0.12V_a\\\Rightarrow \dfrac{14l}{15}=0.12V_a\\\Rightarrow l = \dfrac{15}{14}\times 0.12V_a\\\Rightarrow l = \dfrac{15}{14}\times 0.12\times 343\\\Rightarrow l = \dfrac{15}{14}\times 0.12\times 343\\\Rightarrow l = 44.1\ m

Hence, the length of the rod is 44.1 m.

4 0
3 years ago
Assume the space shuttle's main engines produce 764,576 newtons of thrust, and the shuttle has a mass of 78,018 kg. Why does the
Nady [450]

Weight of anything = (mass) x (gravity in the place where the thing is)

Weight of anything on Earth = (mass) x (9.81 m/s²)

Weight of the shuttle = (78,018 kg) x (9.81 m/s²)

Weight of the shuttle, on Earth = 765,357 Newtons

Thrust of main engines = 764,576 Newtons

Are you starting to see the problem yet ?

The weight of the whole thing standing on the launch pad is 751 Newtons more than the maximum thrust of the main engines, and the engines can't lift it !  Even with all throttles wide open, the main engines alone would need about 175 <em>more</em> pounds of thrust to budge that load off the ground.  Even with the pedal to the metal, with flame and smoke belching out and covering the whole launch complex, the shuttle would just sit there and never leave the pad.

Well, no.  That's not exactly what would happen.  As the fuel in the main monster fuel tank is burned, the weight decreases.  So it would actually happen like this:  After the man announced "Zero !  We have ignition !  All engine running !", the ship would just sit there on the pad ... at first.  It would go nowhere and not even wiggle, <em>UNTIL</em> the first 175 pounds of fuel got burned without accomplishing anything.  The ship would then be 175 pounds lighter.  At that point, the weight would be exactly equal to the thrust of the main engines, and the vertical forces on the ship would be balanced.  Then, as MORE fuel continued to be wasted and the weight continued to decrease, the main engines could just begin to lift the ship off the pad.

So the correct answer is <em>choice-D</em> .  It tells the whole story, quicker than I can tell it.

4 0
3 years ago
Define a method pyramidVolume with double parameters baseLength, baseWidth, and pyramidHeight, that returns as a double the volu
lara31 [8.8K]

Answer:

Explanation:

Its not a good practice to write all the functions including main() in the same class.

But as you opted for this, the code goes here like this:

public class CalcPyramidVolume {

/* Your solution goes here */

static double pyramidVolume(double baseLength, double baseWidth, double pyramidHeight)

{

double Volume,baseArea;

baseArea = baseLength * baseWidth;

Volume = baseArea * pyramidHeight * 1/3;

return Volume;

}

public static void main (String [] args) {

System.out.println("Volume for 1.0, 1.0, 1.0 is: " + pyramidVolume(1.0, 1.0, 1.0));

return;

}

}

And there is not caveat of integer division, as you are declaring all your variables of type double.

3 0
3 years ago
Read 2 more answers
Un recipiente contiene una capa de aceite (densidad 600 kg/m³) de 17.1 cm, sobre otra de agua (densidad 1000 kg/m³) de 28.4 cm d
MAVERICK [17]

Answer:

P=3792.55 Pa

Explanation:

Para resolver este problema, vamos primero a hacer un dibujo de la situación (ver imagen adjunta).

En este caso, tanto el peso del aceite como el peso del agua están ejerciendo una  presión sobre el fondo del recipiente, por lo que la presión total será la suma de ambas presiones. La presión está dada por la equación:

P=\rho gh

por lo que la presión total será:

P_{total}=P_{aceite}+P_{agua}

P_{total}=\rho _{aceite} gh_{aceite}+\rho _{agua} gh_{agua}

y sustituímos (mucho cuidado de convertir las alturas a metros)

P_{total}=(600 kg/m^{3})(9.81 m/s^{2})(17.1x10^{-2}m)+(1000 kg/m^{3}) (9.81 m/s^{2})(28.4x10^{-2}m)

lo cual nos da como resultado:

P=3792.55 Pa

5 0
3 years ago
An astronaut is being tested in a centrifuge. The centrifuge has a radius of 11.0 m and, in starting, rotates according to θ = 0
maxonik [38]

Answer:

ω = 2.9 rad/s, v = 31.7 m/s, α = 0.78 rad/s², a = 91,6 m/s²

Explanation:

I will assume the given equation reads as Ф = 0.39t².

The angular velocity ω is the time derivative of Ф.

ω = 0.78t

The linear velocity v is given by ωr, where r is the radius of the centrifuge.

v = 0.78t r

The tangential acceleration α is the time derivative of ω.

α = 0.78

The radial acceleration a is given by: a = ω²r

a = (0.78t)²r

8 0
3 years ago
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