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choli [55]
2 years ago
11

A very long straight current-carrying wire produces a magnetic field of 20 mt at a distance d from the wire. to measure a field

of 5 mt due to this wire, you would have to go to a distance of:_________
Physics
1 answer:
padilas [110]2 years ago
3 0

The distance covered is 4d.

<h3>What is the distance?</h3>
  • Distance is a measure of how far apart two objects or locations are using numbers.
  • The distance can refer to a physical length or an estimate based on other factors in both daily language and physics (e.g. "two counties over").
  • The terms "distance from A to B" and "distance from B to A" are frequently used interchangeably.
  • A distance function or metric is a technique to describe what it means for components of space to be "near to" or "far away" from each other in mathematics.
  • It is a generalization of the idea of physical distance. Distance is a non-numerical unit of measurement in psychology and the social sciences; psychological distance is the separation of an object from itself along dimensions including time, space, and isolation.

We know that

the magnetic field is inversely proportional to distance.

\dfrac{B_1}{B_2} = \dfrac{D_2}{D_1}

\dfrac{20}{5} = \dfrac{D_2}{d}

D_2 = 4d

To learn more about distance with the given link

brainly.com/question/15172156

#SPJ4

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If the length of a building is 2 1 2 times the width and each dimension is increased by 7 ft, then the perimeter is 266 ft. Find
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The original dimensions of the building is 95 ft × 38 ft.

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Let the original length be 'l' and original width be 'w'.

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Original length (l) = 2\frac{1}{2}\times original\ width

Original width = 'w'.

So, l=2\frac{1}{2}w=\frac{5}{2}w

Now, as per question:

Length and width is increased by 7 ft.

So, new length (l') = l+7=\frac{5w}{2}+7

New width (w') = w+7

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Perimeter is given as:

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Therefore, original width = 38 ft.

Original length is, l=\frac{5\times 38}{2}=\frac{190}{2}=95\ ft

Hence, the original dimensions of the building is 95 ft × 38 ft.

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4 years ago
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