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choli [55]
1 year ago
11

A very long straight current-carrying wire produces a magnetic field of 20 mt at a distance d from the wire. to measure a field

of 5 mt due to this wire, you would have to go to a distance of:_________
Physics
1 answer:
padilas [110]1 year ago
3 0

The distance covered is 4d.

<h3>What is the distance?</h3>
  • Distance is a measure of how far apart two objects or locations are using numbers.
  • The distance can refer to a physical length or an estimate based on other factors in both daily language and physics (e.g. "two counties over").
  • The terms "distance from A to B" and "distance from B to A" are frequently used interchangeably.
  • A distance function or metric is a technique to describe what it means for components of space to be "near to" or "far away" from each other in mathematics.
  • It is a generalization of the idea of physical distance. Distance is a non-numerical unit of measurement in psychology and the social sciences; psychological distance is the separation of an object from itself along dimensions including time, space, and isolation.

We know that

the magnetic field is inversely proportional to distance.

\dfrac{B_1}{B_2} = \dfrac{D_2}{D_1}

\dfrac{20}{5} = \dfrac{D_2}{d}

D_2 = 4d

To learn more about distance with the given link

brainly.com/question/15172156

#SPJ4

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A ball is thrown at 20 m/s from the ground upwards at an angle of elevation of 30°. How far away does it land? 35.35 m
mestny [16]

Answer:

35.35 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 20 m/s

Angle of projection (θ) = 30°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =.?

The range (i.e how far away) of the ball can be obtained as follow:

R = u² Sine 2θ /g

R = 20² Sine (2×30) / 9.8

R = 400 Sine 60 / 9.8

R = (400 × 0866) / 9.8

R = 346.4 / 9.8

R = 35.35 m

Therefore, the range (i.e how far away) of the ball is 35.35 m

8 0
3 years ago
What creates a magnetic field?
kolbaska11 [484]

Answer:

moving electric charges

4 0
2 years ago
HELP PLEASE!!!
Andru [333]

Answer:

It is si-32

Explanation:

5 0
2 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 19 cm apart. The sound
Roman55 [17]

Answer:

a.96cm

b.77cm

Explanation:

Highest intensity,d_1=19cm

Lowest intensity,d_2=29cm

d_1+d_2=19+29=48cm  

48cm is the distance for half-wave, wavelength =48cm*2=96cm

b. From a, above we know that half-wavelength is 48cm

Also, the distance of known  maximum is 29cm

Next maximum is calculated as:

Next \m\aximum=Last \ Maximum+ \ 0.5Wavelength\\=29cm+48cm\\=77cm

The next maximum will occur at 77cm

6 0
3 years ago
In a certain time period a coil of wire is rotated from one orientation to another with respect to a uniform 0.38-T magnetic fie
juin [17]
<h2>The emf produced is 7.2 V</h2>

Explanation:

When coil is placed in the magnetic field , the flux attached with it can be found by the relation . Flux Ф = the dot product of magnetic field and area of coil .

Thus Ф = B A cosθ

here B is magnetic field strength and A is the area of coil .

The angle θ is the angle between coil and field direction .

When coil rotates , the angle varies . By which the flux varies . The emf is produced in coil due to variation of flux . The relation for this is

The emf produced ξ = - \frac{d\phi}{dt} =  B A sinθ \frac{d\theta}{dt}

Now in the given problem

5 = 0.38 x A x \frac{d\theta}{dt}                            I

Now if the magnetic field is 0.55 T and all the other terms are same , the emf produced

ξ = 0.55 x A x \frac{d\theta}{dt}                              Ii

dividing II by I , we have

\frac{\xi}{5} = \frac{0.55}{0.38} = 1.45

or ξ = 7.2 V

6 0
3 years ago
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