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olchik [2.2K]
2 years ago
15

An object has a momentum of 4,000 kg-m/s and a mass of 115 kg. It crashes into another object that has a mass of 100 kg, and the

two objects stick together. If the momentum is conserved, what is the new velocity of the combined object? Round to the nearest hundredth.
Physics
1 answer:
ANTONII [103]2 years ago
4 0

Answer:

18.60  m/s

Explanation:

Original momentum = mv = 4000        with m = 115    

after collision   m = 115 + 100 = 215 kg

  but the total momentum is still the same (conserved)

          4000 = 215 v      shows v = 18.60 m/s

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How much time will it take to do 33j of work with 11 w of power
Yuri [45]

Time required : 3 s

<h3>Further explanation </h3>

Power is the work done/second.

\tt P=\dfrac{W}{t}\\\\P=power,j/s,watt\\\\W=work, J\\\\t=times=s

 

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3 years ago
A block slides along a frictionless surface with 220 J of kinetic energy. It then goes up a frictionless ramp. When the kinetic
aev [14]

Hello!

For the explanation of this energy conservation exercise, where we'll use <u>energy conservation law</u>, let's see what this principle proposes.

How you should know, mechanical energy conserves in every point, that is to say mechanical energy is same in A point like B point. (Mechanical energy will be represented by "Me")

Once time we know that, let's take the 220 Joules momentum like A point, and when 55 Joules momentum like B point.

Then, let's use the <u>energy conservation principle:</u>

Me(A) = Me(B)

  • We know Mechanical energy in A point, so just lets replace according to our data:

220 J = Me(B)

  • In B point, we know kinetic energy, but <u>we dont know gravitational potential energy</u>, so lets descompose Mechanical energy, into kinetic energy and gravitational potential energy:

220 J = Ke + Gpe

  • We know kinetic energy value, so lets replace it:

220 J = 55 J + Gpe

  • Finally, just clean Gpe and resolve it:

Gpe = 220 J - 55 J = 165 J

Gravitational potential energy is of One hundred sixty five Joules <u>(165 J).</u>

                                                                                  ║Sincerely, ChizuruChan║

8 0
2 years ago
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