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Romashka [77]
3 years ago
12

Chris walks 25 m in the positive direction on a number line, then turns around and walks 15 m in the opposite direction. What is

the magnitude of the displacement of Chris?
A. -10 m
B. 40 m
C. 10 m
Physics
1 answer:
7nadin3 [17]3 years ago
3 0

Answer:

|d|  =  |(25 - 15)|  \\  |d|  = 10 \: m

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Hello There!!

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Read 2 more answers
A proton initially has v=4.0i^−2.0j^+3.0k^ and then 4.0 s later has v=−2.0i^−2.0j^+5.0k^ (in meters per second). For that 4.0 s,
pishuonlain [190]

Answer:

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-18.43^{\circ}\ or\ 161.57^{\circ}

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The magnitude is 1.58113883008\ m/s^2

The angle is

\theta=tan^{-1}\dfrac{a_z}{a_x}\\\Rightarrow \theta=tan^{-1}\dfrac{0.5}{-1.5}\\\Rightarrow \theta=-18.43^{\circ}\ or\ 161.57^{\circ}

The angle between a_{avg} and the positive direction of the x axis is -18.43^{\circ}\ or\ 161.57^{\circ}

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