Ask question

Ask question

All categories

2 years ago

12

Chris walks 25 m in the positive direction on a number line, then turns around and walks 15 m in the opposite direction. What is

the magnitude of the displacement of Chris?
A. -10 m
B. 40 m
C. 10 m

1 answer:

7nadin3 [17]2 years ago

3 0

Answer:

$|d| = |(25 - 15)| \\ |d| = 10 \: m$

You might be interested in

While visiting the beach, you enjoy the warm ocean water, but the sand burns your feet. That night you walk along the beach and

garik1379 [7]

The answer would be B..

Since sand can heat up quickly, it will also cool off quickly. But water takes a long time to heat up and cool down.

8 0

3 years ago

Describe the importance of SI units?

anyanavicka [17]

SI unit is an international system of measurements that are used universally in technical and scientific research to avoid the confusion with the units. Having a standard unit system is important because it helps the entire world to understand the measurements in one set of unit system.

5 0

3 years ago

Read 2 more answers

The force of attraction between a -165.0 uC and +115.0 C charge is 6.00 N. What is the separation between these two charges in m

Simora [160]

Answer:

The distance between the charges is 5,335.026 m

Explanation:

To obtain the forces between the particles, we can use Coulomb's Law in scalar form, this is, the force between the particles will be:

$F = k \frac{q_1 q_2}{d^2}$

where k is Coulomb's constant, $q_1$ and $q_2$ are the charges and d is the distance between the charges.

Working a little the equation, we can take:

$d^2 = k \frac{q_1 q_2}{F}$

$d = \sqrt{ k \frac{q_1 q_2}{F}}$

And this equation will give us the distance between the charges. Taking the values of the problem

$k= 9.00 \ 10^9 \frac{N \ m^2}{C^2} \\q_1 = 165.0 \mu C \\q_2 = 115.0 C\\F=- 6.00$

(the force has a minus sign, as its attractive)

$d = \sqrt{ 9.00 \ 10^9 \frac{N \ m^2}{C^2} \frac{(165.0 \mu C) (115.0 C)}{- 6.00 \ N}}$

$d = \sqrt{ 9.00 \ 10^9 \frac{N \ m^2}{C^2} \frac{(165.0 \mu C) (115.0 C)}{- 6.00 \ N}}$

$d = \sqrt{ 28,462,500 \ m^2}}$

$d = 5,335.026 m$

And this is the distance between the charges.

3 0

3 years ago

Barium, a group 2 element, forms an ionic compound with sulfur, a group 16 element. What is the formula for barium sulfide?

WITCHER [35]

Answer:BaS

Explanation:

Ba- barium

S-sulfur

6 0

2 years ago

Help not to sure with this one need help plz asap

DiKsa [7]

A is the answer for the problem

4 0

3 years ago

Read 2 more answers