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babymother [125]
2 years ago
5

A. assuming a perpetual inventory system and using the weighted average method, determine the weighted average unit cost after t

he october 22 purchase. round your answer to two decimal places.
Physics
1 answer:
Monica [59]2 years ago
8 0

Assuming a perpetual inventory system and using the weighted average method, the weighted average unit is determined as $11.44 after the October 22 purchase.

<h3>What is Weighted Average Cost (WAC)?</h3>

The Weighted Average Cost (WAC) method of inventory valuation in accounting uses a weighted average to establish the COGS and inventory levels.

The price of the products up for grabs is divided by the quantity of them in the weighted average cost technique.

The WAC technique is appropriate under both GAAP and IFRS accounting. Weighted Average Cost (WAC) Method Formula

<h3>Weighted Average Cost</h3>

Weighted Average Unit Costs = [360 units×$12 + (320-180) ×$10] / [360+(320-180)]units}

Weighted Average Unit Costs = $5720 / 500 units

Weighted Average Unit Costs = $11.44

Costs of goods that are offered for sale are calculated using beginning inventory value plus acquisitions.

Units available for sale are the number of units that can be sold by a company or the total number of units that are in its inventory.

To know more about weighted average cost, Visit

brainly.com/question/13543092

#SPJ4

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Naddika [18.5K]

First one I believe but im not completely sure

8 0
3 years ago
Ohm’s law is I = V ÷ R. What is the current of a circuit with a 3.0-volt battery and 1.0 ohm of resistance? The current of a cir
Angelina_Jolie [31]
Current = voltage \ resistance
x= 3 \ 1
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7 0
3 years ago
Read 2 more answers
A car moving at 10.0 m/s encounters a depression in the road that has a circular cross-section with a radius of 30.0 m. What is
Dennis_Churaev [7]

Answer:

F = 789 Newton

Explanation:

Given that,

Speed of the car, v = 10 m/s

Radius of circular path, r = 30 m

Mass of the passenger, m = 60 kg

To find :

The normal force exerted by the seat of the car when the it is at the bottom of the depression.

Solution,

Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.

N=mg+\dfrac{mv^2}{r}

N=m(g+\dfrac{v^2}{r})

N=60\times (9.81+\dfrac{(10)^2}{30})

N = 788.6 Newton

N = 789 Newton

So, the normal force exerted by the seat of the car is 789 Newton.

6 0
3 years ago
What's another name for a longitudinal wave?
BlackZzzverrR [31]

Answer: Mechanical longitudinal waves are also called compressional or compression waves, because they produce compression and rarefaction when traveling through a medium, and pressure waves, because they produce increases and decreases in pressure.

Explanation:

mark brainliest pls

7 0
3 years ago
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When Maggie applies the brakes of her car, the car slows uniformly from 15.3 m/s to 0 m/s in 2.23 s. How far ahead of a stop sig
nirvana33 [79]

Answer:

The answer is 34.119m

Explanation:

You need to pay attention to the word "uniformly". It means there is no acceleration thus the physics of this problem respond to the uniform rectilinear motion equations:

  • Xf = Xo + vt
  • v = constant
  • a = 0

where:

  • Xf = Final position
  • Xo = Origin position
  • v = velocity (speed)
  • t = time
  • a = acceleration

Xf = 0 + (15.3)(2.23)

Xf = 34.119m

3 0
4 years ago
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