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marin [14]
1 year ago
9

calculate the mass of dinitrogen tetroxide n2o4 that contains a trillion ×1.001012 nitrogen atoms. be sure your answer has a uni

t symbol if necessary, and round it to 3 significant digits.
Chemistry
1 answer:
Darina [25.2K]1 year ago
6 0

The mass of dinitrogen tetroxide the number of Nitrogen atoms are 46 x 10^9 gram

Given:

number of nitrogen atoms = 1 x 10^12 atoms

To Find:

mass of dinitrogen tetroxide

Solution:

From the molecular formula of dinitrogen tetraoxide;

molar mass of dinitrogen tetraoxide = 92 g/mol

92 g of dinitrogen tetraoxide contains 2 atoms of nitrogen

x g of dinitrogen tetraoxide will contain 1 * 10^12 atoms of nitrogen

x = 92*1* 10^ 9/2

x = 46 x 10^9 gram

Hence, the number of Nitrogen atoms are

Hence, the number of Nitrogen atoms are 46 x 10^9 gram

Learn more about Mass here:

brainly.com/question/26150306

#SPJ4

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Explanation:

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3 years ago
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Explanation:

Formula to calculate osmotic pressure is as follows.

 Osmotic pressure = concentration × gas constant × temperature( in K)

Temperature = 25^{o} C

                      = (25 + 273) K

                      = 298.15 K  

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Putting the given values into the above formula as follows.

       0.698 = C \times 0.082 \times 298.15 K


               C = 0.0285

This also means that,

  \frac{\text{moles}}{\text{volume (in L)}} = 0.0285

So,     moles = 0.0285 × volume (in L)

                      = 0.0285 × 0.100

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}

Now, let us assume that mass of C_{12}H_{23}O_{5}N = x grams

And, mass of C_{12}H{22}O_{11} = (1.00 - x)

So, moles of C_{12}H_{23}O_{5}N = \frac{mass}{\text{molar mass}}

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Now, moles of C_{12}H_{22}O_{11} = \frac{(1.00 - x)}{342}

                   = \frac{x}{369} + \frac{(1.00 - x)}{342}

                  = 2.85 \times 10^{-3}

             = x = 0.346

Therefore, we can conclude that amount of C_{12}H_{23}O_{5}N present is 0.346 g  and amount of C_{12}H_{22}O_{11} present is (1 - 0.346) g = 0.654 g.

4 0
3 years ago
Trust me when I say this.
eimsori [14]

Answer:

thank you

So much this was very nice.

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