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2 years ago

How many atoms of lead are in 3.25 moles of lead

Chemistry

1 answer:

musickatia [10]2 years ago

6 0

Answer: 1.96x10^24 atoms

Explanation:

3.25*6.02214076*10^23 atoms = 1.96x10^24

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_______is the division of the cytoplasm at the end of mitosis.

tankabanditka [31]

Answer: D. CYTOKINESIS

Explanation:

Mitosis ends with telophase, or the stage at which the chromosomes reach the poles. ... Telophase is followed by CYTOKINESIS, or the division of the cytoplasm into two daughter cells.

6 0

2 years ago

What is the relative formula mass of N2O? Ar of N = 14 and Ar of O = 16.

s2008m [1.1K]

We have to calculate formula mass of N₂O.

The answer is: 44

Relative formula mass is the sum of relative atomic mass of constituent atoms in a formula unit of any compound. Relative formula mass is represented as same symbol of relative molecular mass.

To calculate relative formula mass we need to know number of each atom in the formula and then adding atomic masses of all the atoms.

In N₂O, number of N-atom present is equal to 2 and number of O-atom is equal to 1.

Atomic mass of N-atom is 14 and atomic mass of O-atom is 16.

So, formula mass of N₂O is (2 X 14)+16 = 44.

6 0

3 years ago

Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction

AVprozaik [17]

Answer:

The volume of the flask is 20.245 litres .

Explanation:

We are given with following information-

$PV=nRT$ -------- 1

where R = $0.0821L.atom/mole.K$

Molar mass of $PCl_5=208.22g/mole$

The given chemical equation is -

$2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5 _(_s_)$ --------- 2

Now , calculation -

Mass of $PCl_5$ formed = 118g

Molar mass of $PCl_5$ = $208.22g/mole$

Mole = $\frac{mass (g)}{molar mass}$

Therefore , moles of $PCl_5$ formed = $\frac{118}{208.22}$

From equation 2 , we get to know that ,

2mole $PCl_5$ formed from 5 mole $Cl_2 _(_g_)$

Therefore , $\frac{118}{208.22}$ mole $PCl_5$ formed from $\frac{5}{2} \times\frac{118}{208.22}$ mole $Cl_2 _(_g_)$

Moles of $Cl_2 _(_g_)$ used = $\frac{5\times118}{2\times208.22} mole$

R= $0.0821L.atom/mole.K$

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of $Cl_2 _(_g_)$ (n)= $\frac{5}{2} \times\frac{118}{208.22}$ moles

Applying the formula above in 1 equation , that is

PV = nRT

putting the given values -

$1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322$

V = 20.245 litres.

Hence , the volume of the flask is 20.245 litres .

8 0

3 years ago

Magnesium carbonate and sulphuric acid react to form

Mekhanik [1.2K]

Answer:

magnesium sulfate + water + carbon dioxide

Explanation:

4 0

2 years ago

Read 2 more answers

How many moles are in 2.8x10^24 atoms of silicon?

sergejj [24]

Answer:

4.6 mol Si

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 2.8 × 10²⁴ atoms Si

[Solve] moles Si

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up: $\displaystyle 2.8 \cdot 10^{24} \ atoms \ Si(\frac{1 \ mol \ Si}{6.022 \cdot 10^{23} \ atoms \ Si})$
[DA] Divide [Cancel like units]: $\displaystyle 4.64962 \ mol \ Si$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

4.64962 mol Si ≈ 4.6 mol Si

6 0

2 years ago