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Setler [38]
3 years ago
8

How can the motion of an object that is NOT moving change?​

Physics
1 answer:
Semenov [28]3 years ago
6 0
Only if a force acts upon it, it can move.
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LOTS OF POINTSA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.
Svetradugi [14.3K]

Answer:

i) E = 269 [MJ]    ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

i)

E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.

W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

ii ) With the energy calculated at the previous point, we can calculate the speed developed.

E_{k2}=0.5*m*v^2\\269*10^6=0.5*40000*v^2\\v=\sqrt{\frac{269*10^6}{0.5*40000} }\\ v=116[m/s]

8 0
2 years ago
What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a perio
pantera1 [17]
If the period of a satellite is T=24 h = 86400 s that means it is in geostationary orbit around Earth. That means that the force of gravity Fg and the centripetal force Fcp are equal:

Fg=Fcp

m*g=m*(v²/R),
 
where m is mass, v is the velocity of the satelite and R is the height of the satellite and g=G*(M/r²), where G=6.67*10^-11 m³ kg⁻¹ s⁻², M is the mass of the Earth and r is the distance from the satellite. 

Masses cancel out and we have:

G*(M/r²)=v²/R, R=r so:

G*(M/r)=v²

r=G*(M/v²), since v=ωr it means v²=ω²r² and we plug it in,

r=G*(M/ω²r²),

r³=G*(M/ω²), ω=2π/T, it means ω²=4π²/T² and we plug that in:

r³=G*(M/(4π²/T²)), and finally we take the third root to get r:

r=∛{(G*M*T²)/(4π²)}=4.226*10^7 m= 42 260 km which is the height of a geostationary satellite. 
3 0
2 years ago
A useful tool for recoding observations for later analysis is a. This is for science
Gnoma [55]
What type of recording device? You can have a: camera and voice recorder, these are the only type of recording device I can think of

There may be more, but these are the ones I think you are allowed... hope this helps you ☁︎☀︎☁︎
5 0
2 years ago
Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a st
zubka84 [21]

Answer:

R=3818Km

Explanation:

Take a look at the picture. Point A is when you start the stopwatch. Then you stand, the planet rotates an angle α and you are standing at point B.

Since you travel 2π radians in 24H, the angle can be calculated as:

\alpha =\frac{2*\pi *t}{24H}  t being expressed in hours.

\alpha =\frac{2*\pi *11.9s*1H/3600s}{24H}=0.000865rad

From the triangle formed by A,B and the center of the planet, we know that:

cos(\alpha )=\frac{r}{r+H}  Solving for r, we get:

r=\frac{H*cos(\alpha) }{1-cos(\alpha) } =3818Km

6 0
2 years ago
how do scientists know that black holes exist A. by running experiments on the sun B. by observing objects and light around blac
NNADVOKAT [17]

Answer:

E. none of the above

Explanation:

I hope thats right

8 0
2 years ago
Read 2 more answers
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