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nirvana33 [79]
2 years ago
12

Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluor

ide?
CSF + XeF6 → CsXeF7
Chemistry
1 answer:
jenyasd209 [6]2 years ago
4 0

Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we <u>convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles</u>, using its<em> molar mass</em>:

  • Molar mass of CsXeF₇ = 397.193 g/mol
  • 73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇

As <em>1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇</em>, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we <u>convert 0.184 moles of CsF to moles</u>, using the <em>molar mass of CsF</em>:

  • Molar mass of CsF = 151.9 g/mol
  • 0.184 mol * 151.9 g/mol = 27.9 g
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