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1 year ago

What is the act of adding fluid such as distilled water to a powdered or crystaline form?

Chemistry

1 answer:

nata0808 [166]1 year ago

6 0

Reconstitution is the act of adding fluid such as distilled water to a powdered or crystalline form.

Additionally, medications are frequently provided in dry form, such as powders or crystals, which must be reconstituted with liquid before being injected parenterally. To create a specified liquid concentration, a dry ingredient is reconstituted by adding a liquid diluent. To ensure that the drug is reconstituted in the exact concentration, it is crucial to carefully follow the reconstitution instructions. The quantity of fluid used to dilute the drug must also be taken into account when determining the dosage of reconstituted medication to provide to the patient.

Learn more about Reconstitution here-

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How many totals atoms are present in the compound : Mg(OH)2 A. 3 B. 4 C. 5 D. 7

Semenov [28]

1 atom Mg, 2 atoms O and 2 atoms H.

1 + 2 + 2 = 5, so correct answer is C

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2 years ago

Which of the following characteristics describes aerobic organisms.

horsena [70]

Answer: Option (3) is the correct answer.

Explanation:

Aerobic organisms are the organisms which survive and grow in the presence of oxygen.

When oxidation of glucose occurs in the presence of oxygen then it is known as aerobic respiration.

In aerobic respiration, food releases energy to produce ATP which is necessary for cell activity. There is complete breakdown of glucose in aerobic respiration that is why more energy is released. Therefore, aerobic organisms become active.

Thus, we can conclude that characteristics very active, efficient use of energy describes aerobic organisms.

6 0

3 years ago

A mixture of helium, nitrogen and oxygen has a total pressure of 821 mmHg. The partial pressure of helium is 105 mmHg, and the p

skad [1K]

Answer:

Total partial pressure, Pt = 821 mm Hg

Partial pressure of Helium, P1 = 105 mm Hg

Partial pressure of Nitrogen, P2 = 312 mm Hg

Partial pressure of Oxygen, P3 = ? mm Hg

According to Dalton's law of Partial pressures,

Pt = P1 + P2 + P3

So, P3 = 404 mm Hg

4 0

2 years ago

You remove the pot of boiling hot water and set it on a cooler part of the stove. which mechanism is responsible for cooling the

kolbaska11 [484]

All of the mechanisms work together to cool the pot of boiling water. Hope this helps!

3 0

3 years ago

The rate constant k for a certain reaction is measured at two different temperatures temperature 376.0 °c 4.8 x 108 280.0 °C 2.3

9966 [12]

Answer:

The activation energy for this reaction = 23 kJ/mol.

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Where,

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314×10⁻³ kJ / K mol

$k_2=2.3\times 10^8$

$T_2=280\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (280 + 273.15) K = 553.15 K

$T_2=553.15\ K$

$k_1=4.8\times 10^8$

$T_1=376\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (376 + 273.15) K = 649.15 K

$T_1=649.15\ K$

So,

$\left(\ln \left(\:\frac{4.8\times \:\:\:10^8}{2.3\times \:\:\:10^8}\right)\right)\:=-\frac{E_a}{8.314\times \:10^{-3}\ kJ/mol.K}\times \:\left(\frac{1}{649.15\ K}-\frac{1}{553.15\ K}\right)$

$E_a=-\frac{10^{-3}\times \:8.314\ln \left(\frac{10^8\times \:4.8}{10^8\times \:2.3}\right)}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=-\frac{\frac{8.314\ln \left(\frac{4.8}{2.3}\right)}{1000}}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=22.87\ kJ/mol$

The activation energy for this reaction = 23 kJ/mol.

6 0

2 years ago