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bezimeni [28]
3 years ago
15

Explain why some metals are extracted by heating their oxides with carbon, but some metals cannot be extracted in this way

Chemistry
1 answer:
Oxana [17]3 years ago
8 0

Answer:

This happens because a metal is less reactive than carbon and it can be extracted from its oxides by heating with carbon. The carbon displaces metal from the compound and removes the oxygen from the oxide.

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Someone please answer all 5 steps on this density question please.
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Answer:

what is this question in the physics

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3 years ago
Which of these shows a volume of 255 mililiters expressed in liters
-Dominant- [34]
The 1000 to I think that maybe
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Calculate the amount (in moles) of gas which occupies 250cm³ at STP
Elis [28]

Answer:

0.01

Explanation:

volume of 22.4 L (22,400 ml) at s.t.p. 250 ml out of 22,400 ml is 0.01 rounded, therefore I assume that is the answer. About 0.01 mole occupies 250 cm3 at s.t.p.

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Which of the following is not a property of water? Hydrogen bonding causes a high surface tension. Hydrogen bonds exist only in
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3 years ago
Analysis of a rock sample shows that it contains 6.25% of its original uranium-235. How old is the rock? How do you know?
nadya68 [22]

Answer:

2.82\cdot 10^9 y

Explanation:

A radioactive isotope is an isotope that undergoes nuclear decay, breaking apart into a smaller nucleus and emitting radiation during the process.

The half-life of an isotope is the amount of time it takes for a certain quantity of a radioactive isotope to halve.

For a radioactive isotope, the amount of substance left after a certain time t is:

m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}} (1)

where

m_0 is the mass of the substance at time t = 0

m(t) is the mass of the substance at time t

\tau is the half-life of the isotope

In this problem, the isotope is uranium-235, which has a half-life of

\tau=7.04\cdot 10^8 y

We also know that the amount of uranium left in the rock sample is 6.25% of its original value, this means that

\frac{m(t)}{m_0}=\frac{6.25}{100}

Substituting into (1) and solving for t, we can find how much time has passed:

t=-\tau log_2 (\frac{m(t)}{m_0})=-(7.04\cdot 10^8) log_2 (\frac{6.25}{100})=2.82\cdot 10^9 y

5 0
4 years ago
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