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gulaghasi [49]
2 years ago
8

Approximately what is the smallest detail observable with a microscope that uses ultraviolet light of frequency 1.72 x 1015 hz?

provide the solution: __________ x 10-7 m
Physics
1 answer:
Afina-wow [57]2 years ago
8 0

The solution is λ=2.5×10^-7 m

Frequency, speed of light, and wavelength are related by the formula

c = fλ ⇒ λ =c/f

Where c = speed of light ,f = frequency, λ= wavelength

Plug in the value of c = 3 × 10^8 m/s and f = 1.2 × 10^15 Hz in the above equation and solve for the value of λ

λ = 3 × 10^8 ms^-1/1.2 × 10^15 Hz

λ=2.5×10^-7 m

The number of waves that pass a fixed point in unit time; also, the number of cycles or vibrations undergone during one unit of time by a body in periodic motion.

learn more about frequency here:

brainly.com/question/5102661

#SPJ4

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Energy in a capacitor can be defined as

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At the same time capacitance can be defined as,

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Replacing with our values we have that,

C = (8.85*10^{-12})(\frac{0.0451}{2.51*10^{-3}})

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E = \frac{1}{2} (1.5901*10^{-10})(575)^2

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E = \frac{1}{2} \frac{Q^2}{C}

E = \frac{1}{2} (\frac{(9.1425*10^{-8})^2}{3.9754*10^{-11}})

E = 1.051*10^{-4} J

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W = 1.051*10^{-4} J -2.628*10^{-5}J

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So, the height of the tower is 10.16 m.

4 0
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