Answer : The molality of the solution is, 0.788 mole/Kg
Solution : Given,
Mass of solute, 
= 25 g
Mass of solvent, 
= 125 g
Molar mass of solute, = 253.8 g/mole
Molality : It is defined as the number of moles of solute present in one kilogram of solvent.
Formula used :
Now put all the given values in this formula, we get the molality of the solution.
Therefore, the molality of the solution is, 0.788 mole/Kg
Answer:
1.20 × 10³ torr
Explanation:
Step 1: Given data
- Initial pressure (P₁): 822 torr
- Initial temperature (T₁): 325 K
- Final temperature (T₂): 475 K
Step 2: Calculate the final pressure of the gas
Considering the constant volume, if we assume the gas behaves ideally, we can calculate its final pressure using Gay-Lussac's law.
P₁/T₁ = P₂/T₂
P₂ = P₁ × T₂/T₁
P₂ = 822 torr × 475 K/325 K = 1.20 × 10³ torr
Answer:
= 7234.5Joules
Explanation:
Q = (mcΔT)ice + (mΔH)melting +(mcΔT)water
= (10.5g)(2.06J/g°C)[0°C-(-20°C)+(10.5g)(2257J/g)+(10.5g)(4.184J/g°C(75°C - 0°C)
= [(10.5)(2.06)(20) + (10.5)(2257) + (10.5)(4.184)(75)]J
= 432.6J + 3507J + 3294.9J
= 7234.5Joules
Answer:
H2O2 → H2O + 1/2O2
Explanation:
0.0800 mol of H2O2 decomposed into 0.0800 mol of H2O and 0.0400 mol of O2
H2O2 → H2O + 1/2O2 - Descomposition reaction.
