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Slav-nsk [51]
2 years ago
6

Which types of changes must follow the law of conservation of mass? (2 points)

Chemistry
1 answer:
Oksana_A [137]2 years ago
4 0
Both Physical and chemical changes.
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Your aunt is sipping on iced tea and fanning herself during a hot South Carolina summer day. You tell her that there is enough e
mash [69]

Answer:

Isn't this like having enough energy to supply the world for centuries with just 1% of the sea's force?

Explanation:

I guess it's because the amount of energy in it can supply energy.

3 0
2 years ago
The analysis of a hydrocarbon revealed that it was 85.7% C and 14.3% H by mass. When 1.77 g of the gas was stored in a 1.500-L f
gtnhenbr [62]

Answer:

The formula of hydrocarbon = C_3H_6

Explanation:

Moles =\frac {Given\ mass}{Molar\ mass}

% of C = 85.7

Molar mass of C = 12.0107 g/mol

% moles of C = 85.7 / 12.0107 = 7.14

% of H = 14.3

Molar mass of H = 1.00784 g/mol

% moles of H = 14.3 / 1.00784 = 14.19

Taking the simplest ratio for C and H as:

7.14 : 14.19 = 1 : 2

The empirical formula is = CH_2

Also, Given that:

Pressure = 508 Torr

Temperature = 17 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (17 + 273.15) K = 290.15 K  

Volume = 1.500 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637 L.torr/K.mol

Applying the equation as:

508 Torr × 1.500 L = n × 62.3637 L.torr/K.mol × 290.15 K  

⇒n = 0.0421 moles

Given that :  

Amount  = 1.77 g

Molar mass = ?

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0421\ moles= \frac{1.77\ g}{Molar\ mass}

Molar mass of the hydrocarbon = 42.04 g/mol

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 1×12 + 2×1= 14 g/mol

Molar mass = 42.04 g/mol

So,  

Molecular mass = n × Empirical mass

42.04 = n × 14

⇒ n = 3

<u>The formula of hydrocarbon = C_3H_6</u>

5 0
3 years ago
If 9.6 X 1021 molecules of hydrogen are reacted with excess nitrogen, how many liters of ammonia can be produced at STP?
diamong [38]

The volume of NH₃ produced at STP : 0.237 L

<h3>Further explanation</h3>

Reaction

N₂ + 3H₂ → 2NH₃

1 mol = 6.02 x 10²³ particles

9.6 X 10²¹ molecules of Hydrogen, mol :

\tt \dfrac{9.61\times 10^{21}}{6.02\times 10^{23}}=1.596\times 10^{-2}~moles

mol H₂ : mol NH₃ = 3 : 2

mol NH₃ :

\tt \dfrac{2}{3}\times 1.596\times 10^{-2}=0.0106

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). <em>At STP, Vm is 22.4 liters/mol.</em>

The volume of NH₃ :

\tt 0.0106\times 22.4=0.237~L

<em />

8 0
2 years ago
Oxygen is denoted as 16O *. How many protons and neutrons does an oxygen atom have?
Lena [83]
I believe the oxygen atom has 8 protons and 8 neutrons.
7 0
3 years ago
Read 2 more answers
Which of the following compounds will be most soluble in ethanol (CH3CH2OH)?hexane (CH3CH2CH2CH2CH2CH3)ethylene glycol (HOCH2CH2
jonny [76]

Answer:

Ethylene glycol

Explanation:

Solubility results when there is some kind of interaction between the solute and its solvent. In the case of ethylene glycol, it could form intermolecular hydrogen bonds with ethanol and is hence miscible with ethanol in all proportions.

6 0
3 years ago
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