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rosijanka [135]
2 years ago
13

A cyclist travels from point A to point B for 10 minutes. During the first 2.0 minutes of her trip, she maintains a uniform acce

leration of 0.076 m/s2. She then travels at constant velocity for the next 5.0 minutes. Next, she decelerates at a constant rate so that she comes to a rest at point B 3.0 minutes later
What is the acceleration during the last 3.0 minutes
Physics
1 answer:
bogdanovich [222]2 years ago
6 0

Answer:

im not really good at explaining, but i found this website url:

https://www.numerade.com/questions/a-cyclist-travels-from-point-a-to-point-b-in-10-min-during-the-first-20-min-of-her-trip-she-maintain/

same question just with the explanation

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From hottest to coolest, the order of the spectral types of stars is _________. From hottest to coolest, the order of the spectr
Dimas [21]

Answer:

OBAFGKM

Explanation:

Most stars are classified using the Morgan-Keenan system, which consists of assigning a letter to the star depending on its temperature. The hottest stars are type O, and the coldest stars are type M. As for their color, the coldest stars tend to have red color and the hottest have blue colors.

Within each of these divisions (OBAFGKM), there is another division that are the numbers from 0 to 9: 0 is hotter and 9 colder, to get a better classification of a star.

The order of the letters of the Morgan – Keenan system classification, according to the temperatures is as follows:

O: temperatures greater than 33,000K

B: temperatures between 10,000K and 33,000K

A: temperatures between 7,500K and 10,000K

F: temperatures between 6000K and 7.500K

G: temperatures between 5,200K and 6,000K

K: temperatures between 3,700k and 5,200K

M: temperatures below 3,700 K

6 0
4 years ago
A quarterback takes the ball from the line of scrimmage, runs backward for 12.1 yds, then runs sideways parallel to the line of
Over [174]

Answer:

The answer is 35.45 yds

Explanation:

You have to picture this to be able to understand it better (see attachment).

Start at the origin which is when the quarterback (QB) takes the ball. He runs backwards 12.1 yards, runs sideways for 19.8 yards (it doesn´t matter if he runs right or left), then he throws the ball forward 41.5 yards. If you look at the attachment, you can see I drew the path that the football followed. And then connected the dots from the origin and finish. The distance between those two points is the magnitude of the resultant displacement.

In order to calculate it, all you need to do is use the Pythagoream theorem, which says that the square of the hypotenuse equals the sum of the squares of the legs a and b of the triangle rectangle.

  1. R^{2} = a^{2} + b^{2} then solve for R
  2. R = \sqrt{a^{2}+b^{2}  }

In this case, you know the length of leg a to be 19.8 yards which how much it moves sideways. And then, to get the length of leg b, all you need to do is substract how much it moved backwards from the 41.5yards forward displacement. This results in b leg being 29.4 yards long.

Now you have a triangle with:

  • a = 19.8 yards
  • b = 29.4 yards

Substituting this numbers in the equation:

  • R = \sqrt{19.8^{2}+29.4^{2}  }
  • R = 35.45 yards

3 0
3 years ago
What is the net force of a 25 g object with an acceleration of 3 m/s^2?
sasho [114]

Answer:

F = 0,075N

Explanation:

4 0
3 years ago
as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p
miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

E = (3)(230\ m/s)(0.61\ T)Sin90^o

<u>E = 420.9 N/C</u>

3 0
3 years ago
11. Will the cube in#10 float in water? Will it float in benzene?
densk [106]
Where is the cube I don't see any picture?
5 0
4 years ago
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