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N76 [4]
2 years ago
7

A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at

32.4° above the forward direction. Find the magnitude and direction (relative to the forward direction) of the resultant force which these engines exert on the rocket.
Physics
1 answer:
faust18 [17]2 years ago
8 0

The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

<h3>What is the resultant force the two engines exert on the rocket?</h3>

The resultant force on the rocket is calculated thus:

The 513N thrust is resolved into vertical and horizontal components;

Horizontal component: 513N cos(32.4°) = 433.14 N

Vertical component: 513N sin(32.4°) = 274.88 N

Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N

Total force at right angles:

0 + 274.88 N = 274.88 N

The resultant force (F) is then given as follows:

F² = a² + b²

F² = (1158.14 N)² + (274.88 N)²

F = √1,416,847.27

F = 1,190.3

To find the direction:

tan X 274.88 N / 1,158.14 N

X = tan⁻¹ 0.237346089419241

X = 13.35°

Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.

Learn more about resultant force at: brainly.com/question/17434363

#SPJ1

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ElenaW [278]

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5 0
3 years ago
You can describe the _______________ of an object by saying it is moving in a straight line or is curved around another object.
velikii [3]

Answer:

You can describe the<u> motion </u>of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its <u> position </u> in relation to another object. The second object acts as a<u> reference</u> point. When an object changes position, you know it has motion. Motion can also be described by finding an object's <u>speed  </u>or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called <u>velocity</u>

Explanation:

In the given answer-

<u>Motion</u> is defined as - the change in the movement or position of any object  or body.

<u>Position</u> is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.

<u>Reference poin</u>t is a fixed point with regards to which any object or body changes its position. It is also called reference origin.

<u>Speed</u> is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).

<u>Velocity</u> is defined as the rate of speed per unit time. It is a vector quantity (quantity depending upon both magnitude and direction ).

7 0
3 years ago
(eText prob. 4.25 with some values changed) Air enters a diffuser of a jet engine operating at steady state at 2.65 psia, 389◦R,
krek1111 [17]

Answer:

V_2 = 45.44m/s

Explanation:

We have to many data in different system, so we need transform everything to SI, that is

P_1 = 2.65 Psi = 18.271 kPa\\T_1= 389\°R = 216 K\\V_1 = 869ft/s = 264m/s\\T_2 = 450\°R = 250K

When we have all this values in SI apply a Energy Balance Equation,

\dot{Q}_{cv}-\dot{W}_{cv}+\dot{m}[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0

Solving for V_2

V_2 = \sqrt{V_1^2+2(h_1-h_2)}

From the table of gas properties we calculate for T_1 = 216K and T_2 = 250K

h_1 = 209.97+(219.97-209.97)(\frac{216-210}{220-210})

h_1 = 215.97kJ/kg

For T_2;

h_2 = 250.05kJ/kg

Substituting in equation for V_2

V_2 = \sqrt{V_1^2+2(h_1-h_2)}

V_2 = \sqrt{265^2+2(215.97-250.05)*10^3}\\V_2 = 45.44m/s

4 0
3 years ago
An elevator is moving downward when someone presses the emergency stop button. The elevator comes to rest a short time later. Gi
OLga [1]

Answer:

<em>Answer:  - , + </em>

Explanation:

<u>Velocity and Acceleration </u>

In general terms, velocity and acceleration in the plane are both vectors with two components. They don't have 'sign' but magnitude and direction. If we know motion is restricted to a simple line, then we can define the positive and negative references.

In vertical motion, the positive reference is commonly pointed upwards, but if we chose the opposite way, the results shouldn't change in magnitude, just their signs. Let's choose like proposed, the positive direction upwards.

Since the elevator was moving downwards, its velocity is negative. When the button is pushed, it continues to move downwards, but slower. Its velocity is still negative.

The acceleration has the same sign as the velocity if it tends to increase the magnitude of the object, and is negative in the opposite case. Let's look at the formula

\displaystyle a=\frac{v_f-v_o}{t}

In this case, v_f=0 because the elevator will eventually stop, and v_o is negative. It means the acceleration is

\displaystyle a=\frac{-v_o}{t}

It results in a positive value

\boxed{Answer: -,+}

Note: If we chose the opposite references, then the answer would be: +,-

5 0
3 years ago
What is velocity and it’s SI Unit?
svp [43]

Answer:

Velocity is the displacement (change In position of an an object it is similar to distance ) divided by the time taken. SI unit m/s (metre per second)

3 0
3 years ago
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