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mel-nik [20]
3 years ago
15

A current of 1.8 A delivers 2.5 C of charge. How much time was required?

Physics
2 answers:
alexira [117]3 years ago
8 0

Answer: C

Explanation:

fgiga [73]3 years ago
4 0
The current is defined as the amount of charge that flows through a given point in a certain time interval:
I= \frac{Q}{\Delta t}
where Q is the charge and \Delta t the time interval.

In our problem, I=1.8 A and Q=2.5 C, therefore we can find the time interval by re-arranging the previous formula and plugging these numbers into it:
\Delta t=  \frac{Q}{I}= \frac{2.5 C}{1.8 A}=1.4 s

Therefore, C) is the correct answer.
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A mass of 3.0 kg rests on a smooth surface inclined 34° above the horizontal. It is kept from sliding down the plane by a spring
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Answer:

The spring stretched by x = 13.7 cm

Explanation:

Given data

Mass = 3 kg

k = 120 \frac{N}{m}

Angle \theta = 34°

From the free body diagram

Force acting on the box = mg sin\theta

⇒ F = 3 × 9.81 × \sin34

⇒ F = 16.45 N ------- (1)

Since box is attached with the spring so a spring force also acts on the box.

F_{sp} = k x

F_{sp} = 120 x -------- (2)

The net force acting on the body is given by

F_{net} = ma

Since acceleration of the box is zero so

F_{net} = 0

F - F_{sp} = 0

F = F_{sp}

Put the values from equation (1) & (2) we get

16.45 = 120x

x = 0.137 m

x = 13.7 cm

Therefore the spring stretched by x = 13.7 cm

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