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mel-nik [20]
3 years ago
15

A current of 1.8 A delivers 2.5 C of charge. How much time was required?

Physics
2 answers:
alexira [117]3 years ago
8 0

Answer: C

Explanation:

fgiga [73]3 years ago
4 0
The current is defined as the amount of charge that flows through a given point in a certain time interval:
I= \frac{Q}{\Delta t}
where Q is the charge and \Delta t the time interval.

In our problem, I=1.8 A and Q=2.5 C, therefore we can find the time interval by re-arranging the previous formula and plugging these numbers into it:
\Delta t=  \frac{Q}{I}= \frac{2.5 C}{1.8 A}=1.4 s

Therefore, C) is the correct answer.
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The fast train known as the TGV (Train à Grande Vitesse) that runs south from Paris, France, has a scheduled average speed of 21
andrezito [222]

Answer:

Explanation:

Given

average speed of train(v_{avg})=216 kmph\approx 60 m/s

Maximum acceleration=0.05g

Now centripetal acceleration is

a_c=\frac{v^2}{r}

0.05\times 9.8=\frac{60^2}{r}

r=7346.93 m

(b)Radius of curvature=900 m

therefore a_c=\frac{v^2}{r}

v=\sqrt{a_cr}

v=\sqrt{0.05\times 9.8\times 900}

v=\sqrt{441}=21 m/s

8 0
3 years ago
If the Earth rotated more slowly about its axis, your apparent weight would
disa [49]
 <span>If the Earth rotated more slowly about its axis, your apparent weight would 
A) increase. 
B) decrease. 
C) stay the same. 
D) be zero.

</span>A) increase. 
8 0
3 years ago
A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?
Makovka662 [10]

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length f=\frac{R}{2}=\frac{12}{2}=6cm

Now for mirror we know that \frac{1}{f}=\frac{1}{u}+\frac{1}{v}

So \frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}

16.66-0.333=\frac{1}{v}

v = 0.750 m

Now magnification of the mirror is m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025

5 0
3 years ago
There you guys go no one take the points or youll get banned step juice world kid
jasenka [17]

Answer:

thxs ace

Explanation:

6 0
3 years ago
Read 2 more answers
What fraction of the total energy of a SHO is kinetic when the displacement is one third the amplitude
Bas_tet [7]

Answer:

The fraction of kinetic energy to the total energy is \frac{K}{T}=\frac{8}{9}.

Explanation:

displacement is one third of the amplitude.

Let the amplitude is A.

x= A/3

The kinetic energy of the body executing SHM is

K = 0.5 mw^2(A^2 - x^2)\\\\K = 0.5 m w^2 \left ( A^2 -\frac{A^2}{9} \right )\\\\K = 0.5 mw^2\times \frac{8A^2}{9}......(1)

The total energy is

T =0.5 mw^2A^2 ..... (2)

Divide (1) by (2)

\frac{K}{T}=\frac{8}{9}

5 0
2 years ago
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