Answer:
20 m/s
Explanation:
Given:
Δy = 0.02 km = 20 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (9.8 m/s²) (20 m)
v = 19.8 m/s
Rounded to one significant figure, the final velocity is 20 m/s towards the ground.
-1.5 m/s^2 x 1.2 seconds = -1.8 m/s
It is a negative value which means the object slowed down. The object would have originally been going that amount more.
5.0 + 1.8 = 6.8 m/s
answer: 6.8 m/s
Answer:
the mass of the truck is 2 kg.
Explanation:
Given;
mass of the car, m₁ = 3 kg
initial velocity of the car, u₁ = 40 m/s
initial velocity of the truck, u₂ = 60 m/s
let the mass of the truck = m₂
Apply the principle of conservation of linear momemtum;
m₁u₁ = m₂u₂
m₂ = (m₁u₁) / u₂
m₂ = (3 x 40) / (60)
m₂ = 2 kg
Therefore, the mass of the truck is 2 kg.
