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arsen [322]
3 years ago
14

Which group of elements are considered to be in the same family?

Chemistry
1 answer:
mash [69]3 years ago
8 0
A. helium, neon and argon, because they are in the same group or column
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6th grade science i mark as brainliest​
Blababa [14]

Answer:

It's the 4th one. The car is accelerating gradually.

8 0
3 years ago
Arrange the following alkyl bromides in order from most reactive to least reactive in an SN2 reaction: 1-bromo-2-methylbutane, 1
xxMikexx [17]
Primary alkyl halides tend to undergo the SN2 reaction mechanism in nucleophilic substitution since there is less steric hindrance for nucleophilic attack and the carbocations that they form are not as stable as those formed from tertiary alkyl halides. 


1-bromopentane > 1-bromo 2-methylbutane > <span>1-bromo-3-methylbutane</span>> 2-bromo 2-methylbutane
5 0
2 years ago
Read 2 more answers
Give the correct balanced equation for the single replacement reaction of magnesium with aluminum oxide. A) Mg + AlO → MgO + Al
solniwko [45]
Answer is "C".

<em><u>Explanation
</u></em>

Single replacement reaction is a type of reaction which one reactant reacts with another and makes a product by replacing one element by another. 

Mg (Magnesium) reacts with Al₂O₃ (Aluminium oxide) and produces MgO (Magnesium oxide) and Al (Aluminium) as products. Here Al is replaced by Mg. Reaction is 
             Mg + Al₂O₃ → MgO + Al

To balance the reaction equation, both left and right hand sides should have same number of atoms in each element.
Here, 
 <em>Left Hand Side has </em>                                            <em>Right Hand Side has</em>
   Mg = 1 atom                                                         Mg = 1 atom
   Al = 2 atom                                                           Al = 1 atom
   O = 3 atom                                                           O = 1 atom

First step : balance the O atoms in both sides. To do that "3" should be added before MgO. 

Second step : After balancing O atoms, there will be 3 Mg atoms in right hand side. Hence to balance Mg atoms again "3" should be added before Mg in left hand side

Third step : as the final step balance the Al atoms by adding "2" before Al in the right hand side.

Then final balanced equation should be 
              3Mg + Al₂O₃ → 3MgO + 2Al



 
4 0
3 years ago
Read 2 more answers
Calculate the mass of water produced when 2.06 g of butane reacts with excess oxygen.
dem82 [27]
2C4H10 + 13O2 = 8CO2 + 10H2O

1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10

2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O

3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O
8 0
3 years ago
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

5 0
3 years ago
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