Answer: It's the anode broski (B)
Explanation: I'm taking the Chem summer course too broski, this was the correct answer. Cheers broski
Answer:
6.02×10²³ particles / 1 mol
Explanation:
In this question the choices are missed.
For determine the particles of Na, in 0.25 moles we should know that the mole referrs to the Avogadro's number.
1 mol of anything contains 6.02×10²³ entities, that's why we should apply this conversion factor to find the final answer:
0.25 mol . 6.02×10²³ particles / 1 mol = 1.50×10²³ particles
In conclussion: 1.50×10²³ particles of Na are contained in 0.25 moles of Na
Answer : The volume (in mL) of 95% ethanol added would be, 1.39
Explanation :
As we are given that:
Mass of 95 % ethanol = 1.2 g
Density of 95 % ethanol = 0.86 g/mL
Formula used :
Therefore, the volume (in mL) of 95% ethanol added would be, 1.39
