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chubhunter [2.5K]
4 years ago
11

A measurement must include both number and a ?

Chemistry
1 answer:
MatroZZZ [7]4 years ago
4 0
Unit of measurement
ex: ft, in, etc.
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Calculate the hydroxyl ion concentration<br>in 0.02M solution of H2SO4<br>​
sergij07 [2.7K]
In a given solution, the concentration of hydrogen ions and hydroxide ions are related to each other by the following expression:

pH + pOH = 14

where, pH = - log[H+] and pOH = - log [OH-]

In this case, the concentration of sulfuric acid is given as 2.1 x 10^-4 M. Since each molecule of sulfuric acid (H2SO4) contains 2 atoms of hydrogen, the concentration of hydrogen ions in this solution is twice that of sulfuric acid. That is,

Concentration of H+ ions = 2 x 2.1 x 10^-4

= 4.2 x 10^-4 M

This means, pH = -log (4.2 x 10^-4) = 3.38

Since pH + pOH = 14

pOH = 14 - 3.38 = 10.62

This means, 10.62 = -log [OH-]

Solving the equation, we get [OH-] = 2.4 x 10^-11 M.

Hope this helps.
7 0
4 years ago
The burning of 1.0 g of coal produces 8.4 kcal. How many kilojoules are produced?
Andre45 [30]
The conversations need to solve this problem:

1 cal = 4.184 joules
1 Kcal= 1000 calories
1 kj= 1000 joules

or a more direct approach---->> 1 Kcal = 4.184 Kjoules

8.4 kcal (1000 calories/ 1 Kcal) x (4.184 joules/ 1 cal) x (1 Kj/ 1000 joules)= 35.1 Kj

or 8.4 kcal (4.184 Kj/ 1 kcal)= 35.1 Kj (same answer)
7 0
3 years ago
From which plant can benzoic acid be obtained from?​
Sergeeva-Olga [200]

Explanation:

styrax benzoin is what benzoic acid is obtained from

7 0
4 years ago
a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte
IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

Absorbance A = - log₁₀ T

Tm = transmittance measured by spectrophotometer

Tm = 0.44

Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654

True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

S = fraction of stray light = 6%= 6/100 = 0.06

α= 1, ideal case

T = true transmittance of the sample

Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)

i.e; 0.3933

To know more about transmittance click here:

brainly.com/question/17088180

#SPJ4

3 0
2 years ago
HELPP!!!!!!!!!!! Can someone do this for me on paper
aleksley [76]

Answer: I WILL TRY

Explanation:

6 0
3 years ago
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