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4 years ago

29. Ammonia is formed with one nitrogen and three hydrogen atoms. What is the electron configuration of nitrogen? How

Chemistry

1 answer:

masya89 [10]4 years ago

5 0

Answer:

One lone-Pair is present in Ammonia

Explanation:

The number of valence electron in N = 5

The number of Valence electron in H = 1

The formula of ammonia = NH3

Total valence electron in ammonia molecule = 5 +3(1) = 5+3 = 8

The lewis structure suggest that :

Nitrogen completes its octet by sharing the electron pair with 3 hydrogen atoms.

3 electron of Nitrogen are involved in sharing with Hydrogen

So, remaining two electron are left non-bonded . Hence they exist as lone- pair

So, there is only 1 lone pair in the ammonia molecule .

The shape of NH3 is bent according to VSEPR theory . This is so because the presence of 1 lone pair causes more repulsion and occupy more space.

Thus the lone pair is changing the shape of the ammonia molecule . It also increase the dipole moment of the molecule , which gives polarity to it.

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Can anyone help me with this asap?

tresset_1 [31]

Answer:

Explanation:

1) During the diagnosis of thyroid disease a 10 g sample of I-131 is used. After a period of 32 days, how much sample is still radio active.?

Answer:

0.625 g

Explanation:

HL = Elapsed time/half life

32 days/8 days = 4

At time zero = 10 g

At 1st half life = 10/2 = 5 g

At 2nd half life = 5/2 = 2.5 g

At 3rd half life = 2.5 /2 = 1.25 g

At 4th half life = 1.25 / 2 = 0.625 g

After 32 days still 0.625 g of I-131 remain radioactive.

2) what was the original mass of sample Tc-99 that was used to locate the brain tumor If 0.10 g of a sample remains after 30 days? (half life 6 days)

Answer:

0.32 g.

Explanation:

Half life = time elapsed / HL

Half life = 30 days / 6 days = 5

At 5th half life = 0.10 g

At 4th half life = 0.2 g

At 3rd half life = 0.4 g

At 2nd half life = 0.8 g

At 1st half life = 0.16 g

At time zero = 0.32 g

The original amount was 0.32 g.

3) write the beta decay equation of I-131?

Equation:

¹³¹I₅₃ → ¹³¹Xe₅₄ + ⁰₋₁e

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

¹³¹I₅₃ → ¹³¹Xe₅₄ + ⁰₋₁e

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

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3 years ago

The diagram below represents the four stars of matter. Which diagram represents a gas that has been ionized

lara [203]

Answer: Diagram 4

Explanation: Diagram 1 represents a state in which particles are closely packed , thus cannot be a representation of gas.

Diagram 2 represents a state in which particles are loosely packed , thus can be a representation of gas.

Diagram 3 represents a state in which particles are closely packed , thus can be a representation of a solid.

Diagram 4 represents a state in which particles are loosely packed , thus can be a representation of gas. It also represents the particles in ionized form. Particles are existing as ions bearing positive and negative charges.

4 0

3 years ago

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The half reaction of an oxidation-reduction shows that iron gains electrons. What does this electron gain mean or iron?

ale4655 [162]

Answer:

C. its reduced

Explanation:

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3 years ago

How many atoms are in a 158.69 g sample of nickel?

Alchen [17]

<h3>Answer:</h3>

1.6283 × 10²⁴ atoms Ni

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Use Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

158.69 g Ni

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Ni - 58.69 g/mol

Step 3: Convert

Set up: $\displaystyle 158.69 \ g \ Ni(\frac{1 \ mol \ Ni}{58.69 \ g \ Ni})(\frac{6.022 \cdot 10^{23} \ atoms \ Ni}{1 \ mol \ Ni})$
Multiply/Divide: $\displaystyle 1.62827 \cdot 10^{24} \ atoms \ Ni$

Step 4: Check

Follow sig fig rules and round. We are given 5 sig figs.

1.62827 × 10²⁴ atoms Ni ≈ 1.6283 × 10²⁴ atoms Ni

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3 years ago

What is the potential energy of the reactants from the following energy diagram?

slavikrds [6]

The potential energy of the reactants is 200J.
From the energy diagram, the energy of the product formed is 350J; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.

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3 years ago

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