3 years ago

Next, given the equivalent resistance,

Physics

1 answer:

Tju [1.3M]3 years ago

7 0

Answer:

reg21

Explanation:

because i said so

You might be interested in

Will you say thanks, for points?

Ede4ka [16]

Thank you, thx, thank you very much.

6 0

3 years ago

a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m f

goblinko [34]

The effort applied : 200 N

<h3>Further explanation</h3>

Equilibrium rotation

$\large {\boxed {\bold {\sum \tau = 0}}$

F₁.d₁-F₂.d₂=0

F₁.d₁=F₂.d₂

F₁=500 N

d₁=0.5 m

d₂=1.75-0.5=1.25 m

$\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N$

5 0

3 years ago

A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres

Lemur [1.5K]

Answer:

$V_2 = 0.125 m^3$

Work done = = 5 kJ

Explanation:

Given data:

volume of nitrogen $v_1 = 0.08 m^3$

$P_1 = 150 kPa$

$T_1 = 200 degree celcius = 473 Kelvin$

$P_2 = 80 kPa$

Polytropic exponent n = 1.4

$\frac{T_2}{T_1} = [\frac{P_2}{P_1}]^{\frac{n-1}{n}$

putting all value

$\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}$

$\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS$

polytropic process is given as

$P_1 V_1^n = P_2 V_2^n$

$150\times 0.08^{1.4} = 80 \times V_2^{1.4}$

$V_2 = 0.125 m^3$

work done $= \frac{P_1 V_1 -P_2 V_2}{n-1}$

$= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}$

= 5 kJ

4 0

3 years ago

When capacitors are connected in parallel, they have the same:.

Gre4nikov [31]

Answer:

THEY HAVE THE SAME VOLTAGE

3 0

3 years ago

What is the acceleration of a boy on a skateboard if the unr

Alex777 [14]

Answer:

0.26 m/s^2

Explanation:

We're asked to find the acceleration of a body given the net force acting on it and it's mass.

To do this, we use Newton's second law.

8 0

3 years ago

Read 2 more answers