The diagram below represents a sodium atom bonding to a chlorine atom to form sodium chlorine.

A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr

sertanlavr [38]

Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.947 atm

$P_2$ = final pressure of gas = 0.987 atm

$V_1$ = initial volume of gas = 150 ml

$V_2$ = final volume of gas = 144 ml

$T_1$ = initial temperature of gas = $25^0C=(25+273.15)K=298.15K$

$T_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}$

$T_2=298.31K=(298.31-273.15)^0C=25.16^0C$

The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is $25.16^0C$

4 0

3 years ago

Which shell are the valence electrons of a germanium atom in the ground state located

yKpoI14uk [10]

It would be in the fourth shell.

7 0

3 years ago

0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?

ioda

Answer:

V₂ = 1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ = 1.92 L

4 0

3 years ago

A chemist mixes 71.1 g of carbon tetrachloride with 65.4 g of isopropenylbenzene and 4.02 g of 2-ethyltoluene. Calculate the per

-Dominant- [34]

Answer:

% Carbon tetrachloride = 50.6 %

% isopropenylbenzene = 46.5 %

% 2-ethyltoluene = 2.9%

Explanation:

Step 1: Data given

A mixture contains:

71.1 grams of Carbon tetrachloride (CCl4)

65.4 grams of isopropenylbenzene (C9H10)

4.02 grams of 2-ethyltoluene (C9H12)

Step 2: Calculate total mass

Total mass = mass CCl4 + mass C9H10 + mass C9H12

Totam mass = 71.1g + 65.4g + 4.02g

Total mass = 140.52 grams

Step 3: Calculate % of each component:

% component = (mass component/ total mass) *100%

% Carbon tetrachloride = (71.1 / 140.52) *100 %

% Carbon tetrachloride = 50.6 %

% isopropenylbenzene = (65.4 / 140.52) *100%

% isopropenylbenzene = 46.5 %

% 2-ethyltoluene = (4.02/140.52) *100%

% 2-ethyltoluene = 2.9%

50.6% + 46.5% + 2.9% = 100%

5 0

3 years ago

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What is chromatography usese of chromatography ?

victus00 [196]

Explanation:

chromatoghraphy is a laboratory technique for the separation of mixture... ...

chromatoghraphy may be preparative or analytical. The purpose of preparative chromatoghraphy is to separate the components of a mixture for late use, ans is thus a form of purification..... I is your answer it may help you

5 0

3 years ago

Read 2 more answers