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ELEN [110]
3 years ago
7

A magnesium (Mg) atom gives one electron to two atoms of another element, then it takes on a 2+ charge. The two atoms of the oth

er element each form a 1− charge. As a result, the magnesium ion and the two ions of the other element attract and form an ionic bond.
Given the scenario, which of the following elements could behave as described and have two of its atoms receive magnesium's electrons?
Chemistry
2 answers:
bija089 [108]3 years ago
4 0

Answer:

Chlorine

Explanation:

Chlorine, which has 7 in the outer shell.  Only one of those needs one electron to fill the outer shell.

Setler [38]3 years ago
3 0

Answer:

See below

Explanation:

You missed the following elements, but any element with 7 valence electrons could behave like that: Cl, Br, I, F, etc

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Is anyone good at chemistry if so can someone help me please ?<br><br> (NO LINKS)
Mkey [24]

This requires familiarity with the different theories (or concepts) of acids and bases.

On the Arrhenius concept, an acid is a substance that produces an H⁺ ion in water such that the H⁺ concentration increases, and a base is a substance that produces an OH⁻ ion in water such that the OH⁻ concentration increases.

On the Brønsted–Lowry concept, an acid is a substance that donates a proton (which is basically an H⁺ ion) in a solvent, and a base is a substance that accepts a proton in a solvent.

On the Lewis concept, an acid is a substance that accepts an electron pair in a solvent, and a base is a substance that donates an electron pair in a solvent.

The concepts become progressively broader, i.e., the Arrhenius concept is the most restrictive and the Lewis concept is the least restrictive. As a corollary, an Arrhenius acid or base is also both a Brønsted–Lowry acid or base and a Lewis acid or base, respectively; a Brønsted–Lowry acid or base is not necessarily an Arrhenius acid or base, but an Arrhenius acid or base is also a Lewis acid or base, respectively. And finally, a Lewis acid or base may not necessarily be either an Arrhenius or a Brønsted–Lowry acid or base.

So, with the above concepts in mind, we can match the statements in column A with the type of acid or base in column B:

\begin{center}\begin{tabular}{ c c } 1 & Bronsted Lowry acid \\  2 & Bronsted Lowry base \\   3 & Arrhenius acid \\ 4 & Arrhenius base \\ 5 & Lewis base \\ 6 & Lewis acid\end{tabular}\end{center}

6 0
3 years ago
Read the picture :) please and thank you!
lana [24]
It's "C" a sample of dust particles at 0 Pascals
5 0
3 years ago
If you start with 6 mol of nitrogen gas (N2+) what mass (g) of ammonia (NH4) will be produced?
Yanka [14]

Answer:

204g of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.

Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:

Number of mole of NH3 = 12 moles.

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 =..?

Mass = mole x molar mass

Mass of NH3 = 12 x 17

Mass of NH3 = 204g.

Therefore, 204g of NH3 will be produced from the reaction.

3 0
3 years ago
How many moles are in 3.00x 10^22 atoms of He?
sp2606 [1]

Answer:

<h2>0.05 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.0 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.049833...

We have the final answer as

<h3>0.05 moles</h3>

Hope this helps you

3 0
3 years ago
An ideal liquid mixture of benzene and toluene (50% by volume each) is used in a plant at 27°C and 1 atm. Determine (a) the mixt
cestrela7 [59]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

7 0
3 years ago
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