Answer:
v₂> v₃ velocity canoe is more than velocity fishing boat
Explanation:
For this exercise we must define a system consisting of the girl, Sally and the boat, in one case the canoe and in the other the fishing boat; for this system we can use moment conservation
Initial moment. Before the jump
p₀ = (M + m₂) v
Final moment. After the jump
= M v₁ - m₂ v₂
Where m and v are the masses and speed of the canoe
p₀ = p_{f}
(M + m₂) v = M v₁ - m₂ v₂
In the case of changing the canoe for the heaviest fishing boat, the final moment is
p_{f} = M v₁ - m₃ v₃
p₀ = p_{f}
(M + m₃) v = M v₁ - m₃ v₃
Since the canoe is stopped the speed v = 0, we write the speed of each boat
Canoe
0 = M v₁ - m₂ v₂
v₂ = M / m₂ v₁
Fishing boat
0 = M v₁ - m₃ v₃
v₃ = M / m₃ v₁
Since the masses of the fishing boat (m₃) is greater than the mass of the canoe (m₂) the speed of the fishing boat is less than the speed of the canoe, we can find the relationship between the two speeds
v₂ / v₃ = m₃ / m₂
Here you can see what v₂> v₃ velocity canoe is more than velocity fishing boat