Question

An accelerating voltage of 2.50×10³ V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in vacuum toward the center of a viewing screen 35.0cm away. What are(d) the direction of the deflection on the screen caused by the vertical component of the Earth's magnetic field, taken as 20.0μT down? Explain.

Answer 1

The direction of the deflection on the screen caused by the vertical component of the Earth's magnetic field, taken as 20.0uT down is 6.3445*10^-16

Given,

E = Accelerating voltage = 2.47×10³ V

m = Mass of electron

Distance electron travels = 33.5 cm = 0.335 cm

By using the formula,

E = mv^2 /2

v = $\sqrt{2E/m}$

v =  $\sqrt{2*2470*1.6*10^-19 / 9.11*10^-31}$

v = 29455256.08671 m/s

Deflection by Earth's Gravity

Δ = g s^2/v^2 / 2

Δ = 9.81 $\frac{0.335^2}{2955356.08671^2}$ / 2

Δ = 6.3445 * 10^-16 m

Therefore,

Magnitude of the direction on the screen caused by the Earth's Magnetic field is 6.3445*10-16 m

To know more about "Magnetic field"

Refer this link:
https://brainly.in/question/261007?referrer=searchResults

#SPJ4