The smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.
<h3>
Emf induced in the coil</h3>
The emf induced in the coil is calculated as follows;
emf = dФ/dt
where;
- dФ is change in flux
- dt is change in time
0.12 = 5.7/dt
dt = 5.7/0.12
dt = 47.5 s
Thus, the smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.
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Answer:
total time =4.583 hour
Explanation:
We have given total distance = 60 mi
It is given that half of the distance traveled by a speed of 8 mph
We know that 
And second half of the distance traveled by a speed of 36 mph
So time 
So total time = 3.75 + 0.833 =4.583 hour
The current will increase at the same rate the voltage does.
Explanation:
Convert mi/h to ft/s.
60.0 mi/h × (5280 ft/mi) × (1 h / 3600 s) = 88.0 ft/s
Find the acceleration.
a = Δv / Δt
a = (0 ft/s − 88.0 ft/s) / 6.0 s
a = -14.7 ft/s²