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1 year ago

According to the octet rule, if an atom has fewer than 8 electrons in the outer most energy level, what is likely to happen?

Physics

2 answers:

Goshia [24]1 year ago

5 0

Answer:

It will react with other nearby atoms to give, receive or share electrons until it has a full outer shell.

Explanation:

im prolly really late for this one but lol oh well

mina [271]1 year ago

4 0

According to the octet rule, if an atom has fewer than 8 electrons in the outer most energy level, it will react with other nearby atoms to give, receive or share electrons until it has a full outer shell.

The octet rule refers to the tendency of atoms to prefer eight electrons in their valence shell.

If the atom has less than 8 electrons, the atoms tend to react to form more stable compounds.

The discussion of the octet rule does not consider d or f electrons. It is useful for main group elements because only s and p electrons participate in the octet rule.

Atoms are reacted to be as stable as possible. Complete octets are very stable because all orbitals are full. Since atoms with higher stability have less energy, reactions that increase the stability of atoms release energy in the form of heat or light.

Learn more about octet rule here : brainly.com/question/865531

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In this football play the quarterback keeps the ball and goes straight ahead, behind the blocking of the center and the guards.

oksano4ka [1.4K]

Answer:

Explanation:

3 0

3 years ago

A charged object is suspended motionless in the air by the gravitational force pulling it down and an electric force pushing it

Savatey [412]

The charge of the object must be $1.11 \times e^{-5} \text { coulomb }$

Answer: Option C

<u>Explanation:</u>

Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.

Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.

$Electric field, E=\frac{\text { Force }(F)}{q}$

Here, given E = 4500 N/C and F = 0.05 N.

We need to find charge of the object (q)

By substituting the given values, we get

$q=\frac{F}{E}=\frac{0.05 N}{4500 \mathrm{N} / \mathrm{c}}=1.11 \times e^{-5} \text { coulomb }$

6 0

3 years ago

The weight of a standard object defined as having a mass of exactly 2.9 kg is measured to be 28.449 n. in the same laboratory, a

PtichkaEL [24]

Mass of the object m = 2.9 kg
Force F1 = 28.449 N
F1 = m1 x a => a = F / m => 28.449 / 2.9 => a = 9.81, which is gravitational acceleration.
In the same lab, a = g = 9.81, second object F2 = 48.7N = m2 x a
m2 = F2 / a => 48.7 / 9.81 => m2 = 4.96 kg
Mass of the second object m2 = 4.96 kg

4 0

3 years ago

Read 2 more answers

Can the resistors in an "unbalanced" Wheatstone bridge circuit be treated as a combination of series and/or parallel resistors?

OlgaM077 [116]

Answer:

Explanation:

The resistors in a unbalanced wheat stone bridge cannot be treated as a combination of series and parallel combination of resistors.

In case of balanced wheat stone bridge, the resistors can be treated as the combination of series and parallel combination.

Here, In the balanced wheat stone bridge

R1 and R2 be in series and Ra and Rx is series and then their combination is in parallel combination.