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Ierofanga [76]
2 years ago
3

Flag what horizontally applied force will accelerate a 400 kg crate at 1m/s2 across a factory floor against a friction force hal

f its weight?
Physics
1 answer:
pantera1 [17]2 years ago
5 0

A horizontally applied force of 2400 N will accelerate a 400 kg crate at 1 m/s^2.

In the given diagram, the free body diagram (FBD) of a block is shown.

Here the two vertical forces, normal reaction(N) and weight(W) cancel each other while the horizontal forces do not cancel each other and provide acceleration to the block.

According to the given situation,

Applied Force - Frictional Force = ma

Here the frictional force is half the weight of the body 2000 N.

Putting the given values in the above equation,

F - F1 = 400 x 1

F - 2000 = 400

F = 2400 N

Hence, a horizontally applied force of 2400 N will accelerate a 400 kg crate at 1 m/s^2.

To know more about "free body diagram", refer to the following link:

brainly.com/question/24087893?referrer=searchResults

#SPJ4

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One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side
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Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

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H=\sqrt{52}

We can now, calculate the angle between L1 and the 2m segment:

\alpha = atan(\frac{H/2}{2})=60.98°

If we make a sum of forces in the midpoint of the rope we get:

-2*T*cos(\alpha ) + F = 0  where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

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3 years ago
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Explanation:

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