A horizontally applied force of 2400 N will accelerate a 400 kg crate at 1 m/s^2.
In the given diagram, the free body diagram (FBD) of a block is shown.
Here the two vertical forces, normal reaction(N) and weight(W) cancel each other while the horizontal forces do not cancel each other and provide acceleration to the block.
According to the given situation,
Applied Force - Frictional Force = ma
Here the frictional force is half the weight of the body 2000 N.
Putting the given values in the above equation,
F - F1 = 400 x 1
F - 2000 = 400
F = 2400 N
Hence, a horizontally applied force of 2400 N will accelerate a 400 kg crate at 1 m/s^2.
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