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ankoles [38]
3 years ago
13

Part CPart complete Determine the maximum force P that can be applied without causing the two 43-kg crates to move. The coeffici

ent of static friction between each crate and the ground is μs = 0.32.
Physics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

the maximum force will be equal to 134.84 N  

Explanation:

We have given mass m = 43 kg

Coefficient of static friction \mu _s=0.32

Acceleration due to gravity g=9.8m.sec^2

We have to find the maximum force which , when applied there is no movement of crates

This maximum force will be equal to frictional force

Frictional force is given by f=\mu mg=0.32\times 43\times 9.8=134.84N

So the maximum force will be equal to 134.84 N  

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Thomson is responsible for discovering that an atom containing _________
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protons, neutrons, and electrons.  

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Why doesn’t the moon fall toward the earth and smash into it?
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Gravity

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8 0
3 years ago
A horizontal circular platform rotates counterclockwise about its axis at the rate of 0.945 rad/s. You, with a mass of 69.7 kg,
pickupchik [31]

Answer:

317.22

Explanation:

Given

Circular platform rotates ccw 93.1kg, radius 1.93 m, 0.945 rad/s

You 69.7kg, cw 1.01m/s, at r

Poodle 20.2 kg, cw 1.01/2 m/s, at r/2

Mutt 17.7 kg, 3r/4

You

Relative

ω = v/r

= 1.01/1.93

= 0.522

Actual

ω = 0.945 - 0.522

= 0.42

I = mr^2

= 69.7*1.93^2

= 259.6

L = Iω

= 259.6*0.42

= 109.4

Poodle

Relative

ω = (1.01/2)/(1.93/2)

= 0.5233

Actual

ω = 0.945- 0.5233

= 0.4217

I = m(r/2)^2

= 20.2*(1.93/2)^2

= 18.81

L = Iω

= 18.81*0.4217

= 7.93

Mutt

Actual

ω = 0.945

I = m(3r/4)^2

= 17.7(3*1.93/4)^2

= 37.08

L = Iω

= 37.08*0.945

= 35.04

Disk

I = mr^2/2

= 93.1(1.93)^2/2

= 173.39

L = Iω

= 173.39*0.945

= 163.85

Total

L = 109.4+ 7.93+ 36.04+ 163.85

= 317.22 kg m^2/s

4 0
3 years ago
Last week we investigated the black hole at the center of our galaxy, with massMX= 8.5×1036kg. An object whose size is on the or
swat32

Answer:

d=2.38*10^{13}m

Explanation:

We know the mass of the hole, so we define as,

M_x= {8.5*10^{36}}kg

For which centripetal force is equal to gravitational force

\frac{mv^2}{r}=\frac{GMm}{d^2}

Angular velocity is equal to v/r,

w^2r=\frac{6.67*10^{-11}*8.5*10^{36}}{d^2}

As r=1 and w=1, we clear to d,

d^2=5.6695*10^{26}m

d=2.38*10^{13}m

6 0
3 years ago
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