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ankoles [38]
3 years ago
13

Part CPart complete Determine the maximum force P that can be applied without causing the two 43-kg crates to move. The coeffici

ent of static friction between each crate and the ground is μs = 0.32.
Physics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

the maximum force will be equal to 134.84 N  

Explanation:

We have given mass m = 43 kg

Coefficient of static friction \mu _s=0.32

Acceleration due to gravity g=9.8m.sec^2

We have to find the maximum force which , when applied there is no movement of crates

This maximum force will be equal to frictional force

Frictional force is given by f=\mu mg=0.32\times 43\times 9.8=134.84N

So the maximum force will be equal to 134.84 N  

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kolezko [41]

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

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u= 0m/s

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Step two:

We know that

acceleration= velocity/time

also,

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t= 30/23

t= 1.30 seconds

hence

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accelaration= 17.69 m/s^2

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The tour begins on the front porch of your house and ends on the front porch of your house (when you return from work). If we call A to the front porch of the house then the displacement is:

d = A-A = 0

The displacement is zero miles, since the person finishes the journey just where it started (front porch)

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