A jet of water 75m in diameter,issues with a velocity of 30m/s and impinge on a stationary plate which distort its forward motio
1 answer:
Forces exerted by the jet on the plate is=3976N
<h3>How to calculate forces exerted by the jet on the plate?</h3>A force is an effect that can change the motion of an object. A force can generate an object with mass to change its velocity, i.e., to accelerate. Force can also be explained intuitively as a push or a pull. A force has both volume and direction, making it a vector amount.
A jet of water 75m in diameter
velocity = 30m/s
The forces exerted by the jet on the plate is
F=1000×44178×10^-3×30²
=3976N
the jet on the plate work done by Is zero .
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Answer:
23.3808 kW
20.7088 kW
Explanation:
ρ = Density of oil = 800 kg/m³
P₁ = Initial Pressure = 0.6 bar
P₂ = Final Pressure = 1.4 bar
Q = Volumetric flow rate = 0.2 m³/s
A₁ = Area of inlet = 0.06 m²
A₂ = Area of outlet = 0.03 m²
Velocity through inlet = V₁ = Q/A₁ = 0.2/0.06 = 3.33 m/s
Velocity through outlet = V₂ = Q/A₂ = 0.2/0.03 = 6.67 m/s
Height between inlet and outlet = z₂ - z₁ = 3m
Temperature to remains constant and neglecting any heat transfer we use Bernoulli's equation
Work done by pump
∴ Power input to the pump 23.3808 kW
Now neglecting kinetic energy
Work done by pump
∴ Power input to the pump 20.7088 kW
Answer:
Following the ways of dealing with incomplete questions, i was able to get the complete question, please look at the attachment for ans.
