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3 years ago

What are things that need to be considered with respect to the environment when design and construction is occurring?

Engineering

1 answer:

Law Incorporation [45]3 years ago

8 0

Answer:

If you are destroying the environment or habitats or trees. Also if people live nearby. Also if its legal.

Explanation:

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Air, at a pressure of 700 kPa and a temperature of 80°C, flows through a convergent– divergent nozzle. The inlet area is 0.005 m

vodomira [7]

Answer: The complete part of the question is to find the exit velocity

Explanation:

Given the following parameters

Inlet pressure = 700kpa

outlet pressure = 40kpa

Temperature = 80°C = 353k

mass flow rate = 1 kg/s

The application of the continuity and the bernoulli's equation is employed to solve the problem.

The detailed steps and the appropriate formula is as shown in the attached file.

7 0

4 years ago

The pressure at the bottom of an 18 ft deep storage tank for gasoline is how much greater than at the top? Express your answer i

Julli [10]

5.85 psig

Using a specific gravity of 0.75 as an average for red\automobile gasoline.

Water at standard conditions (60 degF) is 2.31 feet = 1 psig

80/2.31 then multiply x .75 to compensate for specific gravity of water being 1.0

4 0

3 years ago

A site is compacted in the field, and the dry unit weight of the compacted soil (in the field) is determined to be 18 kN/m3. Det

suter [353]

Answer:

the relative compaction is 105.88 %

Explanation:

Given;

dry unit weight of field compaction, $W_d_{(field)}$ = 18 kN/m³

maximum dry unit weight measured, $W_d_{(max)}$ = 17 kN/m³

Relative compaction (RC) of the site is given as the ratio of dry unit weight of field compaction and maximum dry unit weight measured

Relative compaction (RC) = dry unit weight of field compaction / maximum dry unit weight measured

$RC = \frac{W_d_{(field)}}{W_d_{(max)}}$

substitute the given values;

$RC = \frac{18}{17} = 1.0588$

RC (%) = 105.88 %

Therefore, the relative compaction is 105.88 %

6 0

3 years ago

Mercury flows inside a copper tube 9m long with a 5.1сm inside diameter at an average velocity of 7.0 m/s. The inside surface te

svp [43]

Answer:

rate of heat transfer = 9085708.80 W

Explanation:

Given:

Inside diameter, D = 5.1 cm

= 5.1 x $10^{-2}$ m

Average velocity, V = 7 m/s

Mean temperature, T = (66+38) /2

= 52°C

Therefore kinematic viscosity at 52°C is ν = 0.104 X $10^{-6}$ $m^{2}$ / s

Prandtl no., Pr = 0.021

We know Renold No. is

Re = $\frac{V\times D}{\nu }$

Re = $\frac{7\times 5.1\times 10^{-2}}{0.104\times 10^{-6}}$

= 3.432 X $10^{6}$

Therefore the flow is turbulent.

Since the flow is turbulent and the ratio of L/D is greater than 60 we can use Dittua-Boelter equation.

Nu = 0.023 $Re^{0.8}$ . $Pr^{0.3}$

= 0.023 x $(3.432 \times10^{6})^{0.8}$ x $(0.021)^{0.3}$

= 1221.52

Since Nu = $\frac{h.D}{k}$

h = $\frac{k\times Nu}{D}$

= $\frac{9.4\times 1221.52}{5.1\times 10^{-2}}$

= 225143.3

Therefore rate of heat transfer, q = h.A(T- $T_{\infty }$

q= 225143.3 x 2πrh ( 66-38)

= 225143.3 X 2π X $\frac{5.1\times10^{-2}}{2}\times 9\times 28$

= 9085708.80 W

6 0

4 years ago

Use the APWA 5600 methodology to compute the 1/25 design discharge for the following catchment. The catchment area consists of 1

sweet [91]

Explanation:

For a given flow rate, open channel flow based design requires larger conduit sizes than those dimensioned based on pressure flow. While it may be more expensive to build designed storm drainage systems

Based on open channel flow, this design procedure provides a margin of safety by providing headroom in the duct to accommodate an increase in flow above the design discharge. Beneath the majority

Under normal conditions, it is recommended that the size of storm drains be based on a gravity flow to full flow criteria or almost full. The design of the pressure flow may be justified in certain cases. As the hydraulic calculations are performed, frequent verification of the existence of the desired flow condition should be performed.

Storm drainage systems can often alternate between pressure and open channel flow conditions from one section to another (Federal Highway Administration, US Department of Transportation, 1996).

For gravity flow conditions, the Manning formula must be edited as described below.

ܳ ൌ

1,486

ܣܴ ଶ / ଷ ܵ ଵ / ଶ

Where:

Q = Discharge, cubic feet per second

A = flow cross-sectional area, square feet

n = Manning roughness coefficient (see Table 5603-1)

ܴ ൌ

R = hydraulic radius, feet

S = slope in feet per foot

P = wet perimeter in feet

5 0

4 years ago