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2 years ago

Can someone help me pls!

Physics

1 answer:

Fiesta28 [93]2 years ago

3 0

Answer:

1) Theories are constructed after there is numerous data collected during the experiment.

2) I think it’s many scientists all over the world accept it as true.

3) to explain natural and physical phenomena

Explanation:

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You want to reduce your energy bills.

aleksandr82 [10.1K]

Answer:

A. 100 Watts

B. 12 Watts

C. the first bulb

Explanation:

A. The formula for power is Work done/time

6000J/60seconds = 100J/s or 100W

B. Another formula for power is Current * Voltage

0.05*240 = 12W

6 0

3 years ago

Tire or false

spayn [35]

1 and 4 are tire.
2 and 3 are not.

8 0

3 years ago

A string of length L, mass per unit length \mu, and tension T is vibrating at its fundamental frequency. What effect will the fo

viva [34]

The fundamental frequency on a vibrating string is given by:

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where

L is the length of the string

T is the tension

$\mu$ is the mass per unit length of the string

Keeping this equation in mind, we can now answer the various parts of the question:

(a) The fundamental frequency will halve

In this case, the length of the string is doubled:

L' = 2L

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2(2L)}\sqrt{\frac{T}{\mu}}=\frac{1}{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{2}$

So, the fundamental frequency will halve.

(b) the fundamental frequency will decrease by a factor $\sqrt{2}$

In this case, the mass per unit length is doubled:

$\mu'=2\mu$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{T}{2 \mu}}=\frac{1}{\sqrt{2}}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{\sqrt{2}}$

So, the fundamental frequency will decrease by a factor $\sqrt{2}$ .

(c) the fundamental frequency will increase by a factor $\sqrt{2}$

In this case, the tension is doubled:

$T'=2T$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu}}=\sqrt{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\sqrt{2}f$

So, the fundamental frequency will increase by a factor $\sqrt{2}$ .

8 0

3 years ago

What will be the answer??

AnnZ [28]

5-a). Acceleration is a vector defined as the rate of change of velocity.
Its magnitude has units of [length/time²]. The SI unit is meter/second².
Its direction is the direction in which velocity is increasing.

5-b). The graph says that the object's speed is not changing.
When we look at any time, from zero to almost 50 minutes, the
object's speed is the same . . . 60 m/s . This will make it easy.

There are 60 seconds in a minute, so 30 minutes = 1,800 seconds.
In every one of those seconds, the object covered 60 meters.
It travelled a total of (60 m/s)·(1,800 s) = 108,000 meters (108 km) .

8 0

4 years ago

A man pulls a 10 kg box at constant speed across the floor with a rope. The tension in the rope is 120 N at an angle of 30°.

Murrr4er [49]

Answer:

98n

Explanation:

5 0

3 years ago