We know that a charge moving in a magnetic field is subject to the force:
F = q · v · B
But we also know that:
F = m · a
Therefore, it must be:
m · a = <span>q · v · B
And solving for a:
</span>a = <span>q · v · B / m
Recall that for a proton:
q = 1.6</span>×10⁻¹⁹ C
m = 1.673×10⁻²⁷ kg
Now, you can find:
a = 1.6×10⁻¹⁹ · 7.0 · 1.7 / <span>1.673×10⁻²⁷
= 1.14</span>×10⁹ m/s²
Hence, the acceleration of the proton is 1.14<span>×10⁹ m/s²</span>.
Answer:
"Apparent weight during the "plan's turn" is 519.4 N
Explanation:
The "plane’s altitude" is not so important, but the fact that it is constant tells us that the plane moves in a "horizontal plane" and its "normal acceleration" is 
Given that,
v = 420 m/s
R = 11000 m
Substitute the values in the above equation,



It has a horizontal direction. Furthermore, constant speed implies zero tangential acceleration, hence vector a = vector a N. The "apparent weight" of the pilot adds his "true weight" "m" "vector" "g" and the "inertial force""-m" vector a due to plane’s acceleration, vector
In magnitude,





Because vector “a” is horizontal while vector g is vertical. Consequently, the pilot’s apparent weight is vector

Which is quite heavier than his/her true weigh of 519.4 N

The Gravitational Force between given objects will be ~

We know that ~

where ~
= mass of 1st object = 70 kg
= mass of 2nd object = 2000 kg
- G = gravitational constant =

- r = distance between the objects = 1 m
Let's calculate the force ~
The following statements apply:
1. Resolution of low boiling solutes is maintained.
2. Retention times of high boiling solutes are decreased.
Temperature programming refers to the process of increasing the temperature of gas chromatography column as a function of time. Temperature programming is usually applied to samples which contain a mixture of components whose boiling points are within narrow ranges