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Ainat [17]
1 year ago
14

A conductor carrying a current I = 15.0 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A

magnetic force per unit length of 0.120 N/m acts on the conductor in the negative y direction. Deter- mine (a) the magnitude
Physics
1 answer:
slavikrds [6]1 year ago
3 0

The magnitude of the magnetic field in the region through the current passes is 8×10⁻³  T.

<h3>What is a magnetic field?</h3>

The magnetic field is defined as the field the magnetic materials generate or when an electric charge moves in a field region that generates the magnetic field.

As we know:

F = ilB

F is the magnetic force

i is the current

l is the length

B is the magnitude of the magnetic field

Here F/l = 0.120 N/m

i = 15 A

B = (F/l)(1\i)

B = (0.120)(1/15)

B = 0.120/15

B = 8×10⁻³  T

Thus, the magnitude of the magnetic field in the region through the current passes is 8×10⁻³  T.

Learn more about the magnetic field here:

brainly.com/question/14848188

#SPJ6

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