Answer:
The beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz
Explanation:
Given;
velocity of wave on the string with lower tension, v₁ = 35.2 m/s
the fundamental frequency of the string, F₁ = 258 Hz
<u>velocity of wave on the string with greater tension;</u>
![v_1 = \sqrt{\frac{T_1}{\mu }](https://tex.z-dn.net/?f=v_1%20%3D%20%5Csqrt%7B%5Cfrac%7BT_1%7D%7B%5Cmu%20%7D)
where;
v₁ is the velocity of wave on the string with lower tension
T₁ is tension on the string
μ is mass per unit length
![v_1 = \sqrt{\frac{T_1}{\mu} } \\\\v_1^2 = \frac{T_1}{\mu} \\\\\mu = \frac{T_1}{v_1^2} \\\\ \frac{T_1}{v_1^2} = \frac{T_2}{v_2^2}\\\\v_2^2 = \frac{T_2v_1^2}{T_1}](https://tex.z-dn.net/?f=v_1%20%3D%20%5Csqrt%7B%5Cfrac%7BT_1%7D%7B%5Cmu%7D%20%7D%20%5C%5C%5C%5Cv_1%5E2%20%3D%20%5Cfrac%7BT_1%7D%7B%5Cmu%7D%20%5C%5C%5C%5C%5Cmu%20%3D%20%5Cfrac%7BT_1%7D%7Bv_1%5E2%7D%20%5C%5C%5C%5C%20%5Cfrac%7BT_1%7D%7Bv_1%5E2%7D%20%3D%20%20%5Cfrac%7BT_2%7D%7Bv_2%5E2%7D%5C%5C%5C%5Cv_2%5E2%20%3D%20%5Cfrac%7BT_2v_1%5E2%7D%7BT_1%7D)
Where;
T₁ lower tension
T₂ greater tension
v₁ velocity of wave in string with lower tension
v₂ velocity of wave in string with greater tension
From the given question;
T₂ = 1.1 T₁
![v_2^2 = \frac{T_2v_1^2}{T_1} \\\\v_2 = \sqrt{\frac{T_2v_1^2}{T_1}} \\\\v_2 = \sqrt{\frac{1.1T_1*(35.2)^2}{T_1}}\\\\v_2 = \sqrt{1.1(35.2)^2} = 36.92 \ m/s](https://tex.z-dn.net/?f=v_2%5E2%20%3D%20%5Cfrac%7BT_2v_1%5E2%7D%7BT_1%7D%20%20%5C%5C%5C%5Cv_2%20%3D%20%5Csqrt%7B%5Cfrac%7BT_2v_1%5E2%7D%7BT_1%7D%7D%20%5C%5C%5C%5Cv_2%20%3D%20%5Csqrt%7B%5Cfrac%7B1.1T_1%2A%2835.2%29%5E2%7D%7BT_1%7D%7D%5C%5C%5C%5Cv_2%20%3D%20%5Csqrt%7B1.1%2835.2%29%5E2%7D%20%3D%2036.92%20%5C%20m%2Fs)
<u>Fundamental frequency of wave on the string with greater tension;</u>
<u />
<u />
Beat frequency = F₂ - F₁
= 270.6 - 258
= 12.6 Hz
Therefore, the beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz
Answer:
a. Exactly the same as the magnitude of the charge of the proton.
Explanation:
The elementary charge (e) is the smallest electric charge that can exist in the universe. Any positive or negative electric charge can be expressed as a multiple of the elementary charge, since is the electric charge carried by a single proton or, equivalently, the magnitude of the electric charge carried by a single electron (-1e).
Answer:a) It is a tie
Explanation:
Given
mass of car is half of SUV
if mass of SUV is 2m so the mass of car is m
SUV can produce twice the force of car i.e. 2 F
so acceleration experienced by SUV
![a_{SUV}=\frac{2F}{2m}](https://tex.z-dn.net/?f=a_%7BSUV%7D%3D%5Cfrac%7B2F%7D%7B2m%7D)
![a_{SUV}=\frac{F}{m}](https://tex.z-dn.net/?f=a_%7BSUV%7D%3D%5Cfrac%7BF%7D%7Bm%7D)
acceleration of Car
![a_{car}=\frac{F}{m}](https://tex.z-dn.net/?f=a_%7Bcar%7D%3D%5Cfrac%7BF%7D%7Bm%7D)
both start with zero initial velocity therefore after few second they will be having same velocity and share same position.
The material that transmits most light is d) clear glass.
Explanation:
Depending on whether objects can transmit light or not, they can be classified into three types:
- Opaque: an object opaque does not transmit light at all (light cannot pass through an opaque object). Examples of opaque objects are metals
- Translucent: translucent objects allow light to pass partially through them. Examples of translucent objects are fluids
- Transparent: transparent objects allow light to pass through them. An example of transparent objects is clear glass
In this problem, we have the following objects:
- Umbrella: it is opaque, light does not pass through it
- Blanket: it is opaque, light does not pass through it
- Mirror: It is opaque, since it reflects light (light does not pass through it)
- Clear glass: it is a transparent object
Therefore, the material that transmits most light is d) clear glass.
Learn more about light:
brainly.com/question/3183125
brainly.com/question/12370040
#LearnwithBrainly
We can only corelate the object's weight with the amount of water it was able to displaced.
If the water displaced was around 400N, then the amount of liter displaced is around 400 N (kg*m/s²) / 9.8 m/s² (earth's gravitational pull) which is equals to ~40.81 liters which should be the objects mass as the best assumption (1kg = 1L). As there is no direct link between the water displaced and actual object weight.