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1 year ago

A train traveling at 27.5 m/s accelerates to 42.2 m/s over 75.0 s. what is the displacement of the train in this time period?

Physics

1 answer:

svlad2 [7]1 year ago

4 0

Answer:

Formular

S=((u+v)/2)t

S= ((27.5+42.2)/2)75

S= 2,613.75 m #

Hope this help!!!

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we need to first get the acceleration before the frictional force which is gotten by using the equation below

$v^{2} = u^{2} + 2aS$

where v = final velocity = 2m/s

u = initial velocity = 0m/s (because the object started from rest)

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we slot in a into the equation below to get frictional force

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