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Nat2105 [25]
3 years ago
13

highlight why it is important to evaluate important assessment studies before any development could be made on the environment​

Chemistry
1 answer:
Kay [80]3 years ago
6 0

Answer:

Essentially, an EIA is designed to identify the potential risks of a project (e.g., infrastructure development such as a dam) to environmental and human well-being and identify measures to eliminate and/or mitigate these risks. This can be done by replacing and/or modifying planned activities to reduce impacts

Explanation:

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When a system is at equilibrium, ________. When a system is at equilibrium, ________. the reverse process is spontaneous but the
zavuch27 [327]

Answer:

When a system is at equilibrium, <u>the process is not spontaneous at either direction.</u>

Explanation:

The process is not spontaneous at either direction , when a system is at equilibrium  ΔG = 0, because -

We know that a negative ΔG indicates a forward-moving phase that is random.

We already know that a positive ΔG implies a non-spontaneous phase going forward.

Thus , here ΔG = 0, so the process is not spontaneous in either direction.

7 0
3 years ago
Classify the following reaction *
hichkok12 [17]

Answer:

double replacement

Explanation:

The reaction equation is given as:

       Pb(NO₃)₂  +  2KI   →   PbI₂ +   KNO₃

This reaction is a double displacement reaction.

In this form of reaction, there is an actual exchange of partners to form new compounds.

      AB + CD →  AD + CD

One of the following condition serves as driving force for the reaction:

  • formation of an insoluble compound
  • formation of water or any other non-ionizing compound
  • liberation of a gaseous product.
5 0
3 years ago
Potassium + water = potassium hydroxide + hydrogen​
Paul [167]

i hope it help you a lot tell it is correct or not

7 0
3 years ago
A compound decomposes by a first-order process. What is the half-life of the compound if 25.0% of the compound decomposes in 60.
amid [387]

Answer : The half-life of the compound is, 145 years.

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time passed by the sample  = 60.0 min

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process = 100 - 25 = 75 g

Now put all the given values in above equation, we get

k=\frac{2.303}{60.0}\log\frac{100g}{75g}

k=4.79\times 10^{-3}\text{ years}^{-1}

Now we have to calculate the half-life of the compound.

k=\frac{0.693}{t_{1/2}}

4.79\times 10^{-3}\text{ years}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=144.676\text{ years}\approx 145\text{ years}

Therefore, the half-life of the compound is, 145 years.

8 0
4 years ago
Pls help me with chem equilibrium part 2!!!! Will mark brainliest
laila [671]
Forward reaction equals the rate of the backward reaction
3 0
3 years ago
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