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Jlenok [28]
1 year ago
8

In which of the three acid-base concepts can water be a product of an acid-base reaction? In which is it the only product?

Chemistry
1 answer:
Archy [21]1 year ago
4 0

Salt and water is formed as product, when Arrhenius acid and Arrhenius base reacts and the reaction is known as neutralization reaction.

<h3>What is Arrhenius acid-base reaction?</h3>
  • The concept of acid and base based on the theory of ionization which was first proposed in 1884 by Svante Arrhenius
  • According to Arrhenius, on dissociation in water the hydrogen-containing compounds which give H+ ions or protons are the acids and  the hydroxide compounds which give OH− ions on dissociation in water are bases.
  • This theory is applicable only to compounds which are dissolved in aqueous solution.

To learn more about Arrhenius acid-base reaction: brainly.com/question/15196401

#SPJ4                                                                                    

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If it takes 645 J of energy to warm a 5.51-g sample of water, how much energy would be required to warm 55.1 g of water by the s
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Answer:

Explanation:If 5.51 g of water needs 645 J of energy to warm then 55.1 g of water needs 6450 J of energy to warm.

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A liquid with weak intermolecular forces will
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Which of the following will lower the rate of reaction? (there are 2 answers to select)
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B. Adding an enzyme to the reaction

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The effectiveness of nitrogen fertilizers depends on both their ability to deliver nitrogen to plants and the amount of nitrogen
densk [106]

Answer:

Ammonia > Urea > Ammonium nitrate > Ammonium sulphate

Explanation:

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Hence % by mass = 14/17 × 100 = 82.35%

% by mass of NH4NO3

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Hence; 28/80.043 × 100 = 34.98%

% by mass of (NH4)2SO4;

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8 0
3 years ago
Determine the approximate density of a Ti-6Al-4V titanium alloy that has a composition of 90 wt% Ti, 6 wt% Al, and 4 wt% V. [Hin
Kamila [148]

Answer:

ρ = 4407.03 kg/m³

Explanation:

The Density of a metal alloy is given by the following equation:

1/ρ = m₁/ρ₁ + m₂/ρ₂ + m₃/ρ₃

where,

ρ = density of allow = ?

ρ₁ = density of Titanium (Ti) = 4540 kg/m³

ρ₂ = density of Aluminum (Al) = 2710 kg/m³

ρ₃ = density of Vanadium (V) = 6110 kg/m³

m₁ = mass fraction of Titanium (Ti) = 90% = 0.9

m₂ = mass fraction of Aluminum (Ti) = 6% = 0.06

m₁ = mass fraction of Vanadium (V) = 4% = 0.04

Therefore,

1/ρ = 0.9/(4540 kg/m³) + (0.06)/(2710 kg/m³) + (0.04)/(6110 kg/m³)

1/ρ = 1.9823 x 10⁺⁴ m³/kg + 0.2214 x 10⁻⁴ m³/kg + 0.0654 x 10⁻⁴ m³/kg

1/ρ =  2.2691 x 10⁻⁴ m³/kg

ρ = 1/(2.2691 x 10⁻⁴ m³/kg)

<u>ρ = 4407.03 kg/m³</u>

5 0
3 years ago
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