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anygoal [31]
3 years ago
10

What is the weight of an object(on earth) that has a mass of 50Kg (g earth=10N/Kg)

Physics
1 answer:
kumpel [21]3 years ago
4 0
W=mg
Therefore W is 50by 10 thus 500N
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Elenna [48]
The first: alright, first: you draw the person in the elevator, then draw a red arrow, pointing downwards, beginning from his center of mass. This arrow is representing the gravitational force, Fg.
You can always calculate this right away, if you know his mass, by multiplying his weight in kg by the gravitational constant
g = 9.81 \frac{m}{s {}^{2} }
let's do it for this case:
f_{g}  = m \times g \\ f _{g}  = 65kg \times 9.81 \frac{m}{s {}^{2} }  = 637.65
the unit of your fg will be in Newton [N]
so, first step solved, Fg is 637.65N
Fg is a field force by the way, and at the same time, the elevator is pushing up on him with 637.65N, so you draw another arrow pointing upwards, ending at the tip of the downwards arrow.
now let's calculate the force of the elevator
f = m \times a \\ f = 65 \times 5 \frac{m}{s {}^{2} }  \\ f = 325n
so you draw another arrow which is pointing downwards on him, because the elevator is accelating him upwards, making him heavier
the elevator force in this case is a contact force, because it only comes to existence while the two are touching, while Fg is the same everywhere
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3 years ago
Are individual organelles (cell structures) living? Explain
Julli [10]
All cells are living however organelles are not living there are no organisms that consist of just a single cell
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Please help me, this is a physics test.
sweet-ann [11.9K]

Answer:

a = 2 [m/s²]

Explanation:

To be able to solve this problem we must make it clear that the starting point when the time is equal to zero, the velocity is 5 [m/s] and when three seconds have passed the velocity is 11 [m/s], this point is the final point or the final velocity.

We can use the following equation.

v_{f}=v_{o}+a*t\\

where:

Vf = final velocity = 11 [m/s]

Vo = initial velocity = 5 [m/s]

a = acceleration [m/s²]

t = time = 3 [s]

11 = 5 + a*3\\6=3*a\\a= 2[m/s^{2} ]

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A 34.00 kg sample of mud has a specific heat of 2,512 J/kg °C.
Elena-2011 [213]

Answer:

B ig lol

Explanation:

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3 years ago
You know the power for a machine and the time it takes to produce that power, what value can you calculate?
Sati [7]

We can calculate the work done by the machine by the mathematical formula,

P = W/t

where, P = Power

W = work done

t = time

6 0
3 years ago
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