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ololo11 [35]
2 years ago
9

Calculate the volume of material whose density is 0.798gcm-3 and a mass 25g

Physics
2 answers:
luda_lava [24]2 years ago
5 0

Explanation:

density equals mass/volume

Elena L [17]2 years ago
4 0

<u>Answer:</u>

 \mathrm{volume = \bf 31.33 \sapce\ cm^{-3}}

<u>Explanation:</u>

To calculate the volume, we can use the following formula:

\boxed{\mathrm{density = \frac{mass}{volume}}}.

In this case,

• density = 0.798 gcm⁻³

• mass = 25 g

Substituting values into the formula:

\mathrm{0.798 \space\ gcm^{-3}= \frac{25 \space\ g}{volume}}

⇒ \mathrm{volume = \frac{25 \space\ g}{0.798 \space\ gcm^{-3}}}

⇒  \mathrm{volume = \bf 31.33 \sapce\ cm^{-3}}

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Answer:

Explanation:

Mass =11.2kg

Constant velocity =3.3m/s

μk=0.25

Since the body is moving in constant velocity, then the acceleration is zero(0).

ΣF = Σ(ma)

The normal force acting on the body is upward and the weight is acting downward

Then ΣFy=0

Therefore, N=W

W=mg=11.2×9.8=109.76N

So, N=W=109.76N

Frictional force is given as

Fr=μkN

Fr=0.25×109.76

Fr=27.44N

Frictional force acting against the motion is 27.44N

Then the forward force moving the body forward

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Since a = 0

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ΣF = 0

F-Fr=0

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3 years ago
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Answer:

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2 years ago
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EleoNora [17]

Answer:

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PE₁ + KE₁ = PE₂ + KE₂

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7 0
3 years ago
The current in a wire varies with time according to the relationship 1=55A−(0.65A/s2)t2. (a) How many coulombs of charge pass a
mario62 [17]

Answer:

(A) Q = 321.1C (B) I = 42.8A

Explanation:

(a)Given I = 55A−(0.65A/s2)t²

I = dQ/dt

dQ = I×dt

To get an expression for Q we integrate with respect to t.

So Q = ∫I×dt =∫[55−(0.65)t²]dt

Q = [55t – 0.65/3×t³]

Q between t=0 and t= 7.5s

Q = [55×(7.5 – 0) – 0.65/3(7.5³– 0³)]

Q = 321.1C

(b) For a constant current I in the same time interval

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3 years ago
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