What seems to make the center of the atom unstable?

A 500 gram mass is connected to a spring and undergoing uniform circular motion. The radius is at 14.5 cm and the applied centri

swat32

To solve the problem it is necessary to apply the concepts related to the Centripetal Force.

By definition the centripetal force is given by

$F_c = \frac{mv^2}{R}$

Our values are defined by

$m=0.5Kg\\F_c = 5.88N \\R = 0.145m+1cm = 0.155m\\v = 1.31m/s$

Therefore replacing in the equation we have to,

$F_c = \frac{mv^2}{R}$

$5.88=\frac{0.5*v^2}{0.155}$

Re-arrange to find V,

$V=\sqrt{\frac{5.88*0.155}{0.5}}$

$V= 1.35m/s$

Therefore the expected velocity of the spinning mass at the new radius is 1.35m/s

6 0

3 years ago

Honey bees can acquire a small net charge on the order of 1 pC as they fly through the air and interact with plants. Estimate th

murzikaleks [220]

Answer:

$3.35\cdot 10^{-16}N$

Explanation:

The force exerted on a charged particle due to a magnetic field is given by:

$F=qvB sin \theta$

where

q is the charge of the particle

v is the velocity of the particle

B is the magnetic field strength

$\theta$ is the angle between the directions of B and v

In this problem we have:

$q=1 pC=1\cdot 10^{-12} C$ is the charge of one honey bee

$v=15 mi/h = 6.7 m/s$ is the velocity of the bee

$B=5.0\cdot 10^{-5} T$ is the average strength of the Earth's magnetic field

$\theta=90^{\circ}$ , because the bee flies east to west while the Earth's magnetic field is south to north

Substituting into the equation, we find:

$F=(1\cdot 10^{-12}C)(6.7 m/s)(5.0\cdot 10^{-5} T)(sin 90^{\circ})=3.35\cdot 10^{-16}N$

7 0

3 years ago

When two 10-Ohm resistors are in parallel in a circuit, what is the net resistor value

Elza [17]

Answer:

Net capacitance

=

let net capacitance be R

1/R = 1/10+1/10

1/R=2/10

1/R=1/5

cross mutiply

R=5

the net capacitance is 5ohms

6 0

3 years ago

Plss help me asap

Travka [436]

c. Wind power can turn turbines to generate electrical power.

Explanation:

The correct statement of all is that wind power can turn turbines to generate electrical power.

This is simply the way wind energy from waves are usually harnessed to produce electricity.

When a metallic conductor passes in between magnetic fields, it induces and generates electricity as it turns.
This is how electricity generating plants are fashioned.
Geothermal energy is not generated from moving water. It is produced from heat within the earth brought to the surface. Power from moving water is hydroelectric power.
Oil is a non-renewable resource
Propane is a non-renewable resource

learn more:

Non-renewable resource brainly.com/question/3386515

#learnwithbrainly

6 0

3 years ago

A pilot flies in a straight path for 1 h 30 min. She then makes a course correction, heading 10 degrees to the right of her orig

atroni [7]

Answer:

The plane is 2353.7 mi from the starting position.

Explanation:

Please, see the attached figure for a graphic representation of the problem.

We have 2 displacement vectors "a" and "b" and a vector "c" that is the sum of vectors "a" plus "b" (c = a + b). The module of "c" will be the distance of the plane from the starting point.

vector a = (xa, ya)

vector b = (xb, yb)

where “xa” and “xb” are the horizontal components of the vectors “a” and “b” respectively and “ya” and “yb” are the vertical components of each vector.

Then, the vector c = a + b will be:

c = (xa + xb, ya + yb)

The module of a vector is calculated using the following expression for a vector “v”:

module of v = $\sqrt{x^{2} + y^{2} }$

Then, the module of c will be:

module of c = $\sqrt{(xa + xb)^{2} + (ya + yb)^{2}}$ = distance from starting point

Then, we have to find the components of vectors “a” and “b”

The distance traveled during the first 1.5 hours of the trip is the module of the vector “a”. Then:

module of a = $\sqrt{xa^{2} + ya^{2} }$ = distance traveled during the first 1.5 hours.

The distance can be calculated using the equation of the position of an object moving in a straight line at constant speed:

x = x0 + v * t

where

x = position at time t

x0 = initial position

v = speed

t = time

Considering x0 as the starting point (x0 = 0)

x = 675 mi/h * 1.5 h = 1012.5 mi

Then:

module of a = $\sqrt{xa^{2} + ya^{2} }$ = 1012. 5 mi

Since the plane moves only on the horizontal (see figure), the "y" component of the vector, "ya", will be 0.

Then:

(1012.5 mi)² = xa²

xa = 1012. 5mi

a = (1012.5 mi, 0)

In the same way, we have fo find the components of the vector “b”. The module of “b” will be the distance traveled during this part of the flight:

module of b = $\sqrt{xb^{2} + yb^{2} }$ = x = x0 + v * t

Considering x0 as the point at which the plane turns (x0 = 0)

x = 675 mi / h * 2 h = 1350 mi

Using trigonometry, we can calculate xb and yb (see figure):

sin angle = opposite / hypotenuse

cos angle = adjacent / hypotenuse

In this case:

opposite = yb

adjacent = xb

hypotenuse = module of “b”

Then:

sin 10° = yb / module of “b”

sin 10° * module of “b” = yb

In the same way:

cos 10° * module of “b” = xb

Since module of “b” = 1350 mi

xb = 1329.5 mi

yb = 234.4 mi

b = (1329.5 mi, 234.4 mi)

The vector c = a+b can now be calculated:

c = (xa + xb, ya + yb)

c =(1012.5 mi + 1329.5 mi, 0 mi + 234.4 mi) = (2342 mi, 234.4 mi)

The module of c will be:

module of c = $\sqrt{(2342 mi)^{2} + (234.4 mi)^{2} }$ = 2353.7 mi

The plane is 2353.7 mi from the starting position.

4 0

3 years ago