A) average acceleration = final velocity - initial velocity / time
 = 7700 - 0 / 11
 = 700ms^-2
B) force = mass x acceleration 
 = (3.05 x 105) x 700
 = 320.25 x 700
 = 224,175N
        
             
        
        
        
Answer:
<em>His angular velocity will increase.</em>
Explanation:
According to the conservation of rotational momentum, the initial angular momentum of a system must be equal to the final angular momentum of the system.
The angular momentum of a system =  'ω'
'ω'
where
 ' is the initial rotational inertia
' is the initial rotational inertia
ω' is the initial angular velocity
the rotational inertia = 
where m is the mass of the system
and r' is the initial radius of rotation
Note that the professor does not change his position about the axis of rotation, so we are working relative to the dumbbells.
we can see that with the mass of the dumbbells remaining constant, if we reduce the radius of rotation of the dumbbells to r, the rotational inertia will reduce to  .
.
From
 'ω' =
'ω' =  ω
ω
since  is now reduced, ω will be greater than ω'
 is now reduced, ω will be greater than ω'
therefore, the angular velocity increases.
 
        
             
        
        
        
Answer:
I hope this helps and I'm not to late
A way the balls behave the same way is by bouncing about 1 time after throwing the balls up. A way the balls act differently is the blue ball is bouncier than all the balls, the red ball bounces about 2 times before stopping, and the green ball doesn’t really bounce except for one time.
Explanation:
you also can use paraphrase to help you reword bye bye!!
 
        
             
        
        
        
Clarify what you mean by ratios?
        
             
        
        
        
Answer:
  t_{out} =  t_{in},      t_{out} =
 t_{in},      t_{out} = 
Explanation:
This in a relative velocity exercise in one dimension,
let's start with the swimmer going downstream
its speed is
          
The subscripts are s for the swimmer, r for the river and g for the Earth
with the velocity constant we can use the relations of uniform motion
             = D /
 = D / 
            D = v_{sg1}  t_{out}
now let's analyze when the swimmer turns around and returns to the starting point
         
           = D /
 = D / 
          D = v_{sg 2}  t_{in}
with the distance is the same we can equalize
            
           t_{out} =  t_{in}
            t_{out} =  t_{in}
 t_{in}
This must be the answer since the return time is known. If you want to delete this time
             t_{in}= D / 
we substitute
             t_{out} = \frac{v_s - v_r}{v_s+v_r} ()
             t_{out} = 