Explanation:
a.) kg(m/s)(1/s) = force (N)
b.) (kg/s)(m/s) = force (N)
c.) (kg/s)(m/s) = force (N)
d.) (kg/s)(m/s) = force (N)
At first glance, this statement seems to be true. But after about a
microsecond of further consideration, one realizes that the statement
would actually set Boyle spinning in his grave, and is false.
Boyle's law states that there is a firm relationship among the pressure,
temperature, and volume of an ideal gas, and that you can't say anything
about how any two of these quantities depend on each other, unless you
also say what's happening to the third one at the same time.
As the pressure of an ideal gas increases, the volume will decrease in
direct proportion to the volume, IF THE TEMPERATURE OF THE GAS
REMAINS CONSTANT.
If you wanted to, you could increase the pressure AND the volume of an
ideal gas both at the same time. You would just need to warm it enough
while you squeeze it.
Answer:
48cm by the minus of difference of 32 CM length 20 CM because of the length of the building
<span>2Kg50m/
s2.5m/
s2<span>2m/
s2</span></span>
Answer:
The correct answer is option A.
Explanation:
Force is defined as push or pull on an object with mass due to which change velocity occurs (acceleration).
![a=\frac{dv}{dt}[tex][tex]m\times \frac{dv}{dt}[tex]We are given with large truck and small car at constant speed, which means that acceleration zero.[tex]a=\frac{dv}{dt}=0](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bdv%7D%7Bdt%7D%5Btex%5D%3C%2Fp%3E%3Cp%3E%5Btex%5Dm%5Ctimes%20%5Cfrac%7Bdv%7D%7Bdt%7D%5Btex%5D%3C%2Fp%3E%3Cp%3EWe%20are%20given%20with%20large%20truck%20and%20small%20car%20at%20constant%20speed%2C%20which%20means%20that%20acceleration%20zero.%3C%2Fp%3E%3Cp%3E%5Btex%5Da%3D%5Cfrac%7Bdv%7D%7Bdt%7D%3D0)
if ,v = constant
Net force on the vehilce
F = Normal - Weight
0 = N = W
N = W
So, the force experienced by the object will be due to its mass, and higher the mass more will be the experienced by an object.So, large truck will experience larger net force.
