The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².
<h3>What will be the maximum acceleration of the truck to avoid tipping over?</h3>
The maximum acceleration is obtained by taking clockwise moments about the tipping point of rotation.
Clockwise moment = Anticlockwise moment
Ft * 1.58 m = F * 0.67 m
where
- Ft is tipping force = mass * acceleration, a
- F is weight = mass * acceleration due to gravity, g
m * a * 1.58 = m * 9.81 * 0.67
a = 4.15 m/s²
The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².
In conclusion, the acceleration of the truck is found by taking moments about the tipping point.
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It would last as long as the applied force continued, or until the accelerating object hit something.
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more deceleration.
in vertical motion downwards => terminal velocity ... raindrops etc
Assuming that the object starts at rest, we know the following values:
distance = 25m
acceleration = 9.81m/s^2 [down]
initial velocity = 0m/s
we want to find final velocity and we don't know the time it took, so we will use the kinematics equation without time in it:
Velocity final^2 = velocity initial^2 + 2 × acceleration × distance
Filling everythint in, we have:
Vf^2 = 0^2 + (2)(-9.81)(-25)
The reason why the values are negative is because they are going in the negative direction
Vf^2 = 490.5
Take the square root of that
Final velocity = 22.15m/s which is answer c